Question

What is an equation for the linear function whose graph contains the points (2, 5) and (3, 0)?

Answer 1

Answer:

y = -5x + 15

Step-by-step explanation:

We'll look for a linear function of the form y = mx + b, where m is the slope and b is the y-intercept.

We can determine a slope from the two given points by calculating a Rise/Run.  Starting at (2,5) and going to (3,0):

Rise = (0 - 5) = -5

Run = (3-2) = 1

Rise/Run = Slope, m) = -(5/1) or -5

Now we have y = -5x + b

To find b, enter either of the two points and solve for b.  I'll use (3,0), because I know my zero multiplication and addition tables by heart.

y = -5x + b

0 = -5(3) + b

b = 15

The equation becomes y = -5x + 15

See attachment.