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Nookie1986 [14]
2 years ago
9

What is an equation for the linear function whose graph contains the points (2, 5) and (3, 0)?

Mathematics
1 answer:
dolphi86 [110]2 years ago
5 0

Answer:

y = -5x + 15

Step-by-step explanation:

We'll look for a linear function of the form y = mx + b, where m is the slope and b is the y-intercept.

We can determine a slope from the two given points by calculating a Rise/Run.  Starting at (2,5) and going to (3,0):

Rise = (0 - 5) = -5

Run = (3-2) = 1

Rise/Run = Slope, m) = -(5/1) or -5

Now we have y = -5x + b

To find b, enter either of the two points and solve for b.  I'll use (3,0), because I know my zero multiplication and addition tables by heart.

y = -5x + b

0 = -5(3) + b

b = 15

The equation becomes <u>y = -5x + 15</u>

See attachment.

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Answer:

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Step-by-step explanation:

Remember BPEMDAS.

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3 years ago
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Find the inverse of f(x)=(x−5)/(−4x−2)
uysha [10]

Answer:

{f}^{ - 1} (x)= \frac{  5 - 2x }{ 4x  + 1}

Step-by-step explanation:

The given rational function is

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Let

y =  \frac{x - 5}{ - 4x - 2}

Interchange x and y

x=  \frac{y- 5}{ - 4y - 2}

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Expand

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Solve for y;

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or

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Therefore

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The dimensions (width and length) of room1 have been read into two variables: width1 and length1. the dimensions of room2 have b
Reika [66]
Hello : 
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Answer:

(2a, b )

Step-by-step explanation:

Given the endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

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