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Nookie1986 [14]
2 years ago
9

What is an equation for the linear function whose graph contains the points (2, 5) and (3, 0)?

Mathematics
1 answer:
dolphi86 [110]2 years ago
5 0

Answer:

y = -5x + 15

Step-by-step explanation:

We'll look for a linear function of the form y = mx + b, where m is the slope and b is the y-intercept.

We can determine a slope from the two given points by calculating a Rise/Run.  Starting at (2,5) and going to (3,0):

Rise = (0 - 5) = -5

Run = (3-2) = 1

Rise/Run = Slope, m) = -(5/1) or -5

Now we have y = -5x + b

To find b, enter either of the two points and solve for b.  I'll use (3,0), because I know my zero multiplication and addition tables by heart.

y = -5x + b

0 = -5(3) + b

b = 15

The equation becomes <u>y = -5x + 15</u>

See attachment.

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Oduvanchick [21]
Im sorry idk this answer

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3 years ago
Can someone help me out with this?
Anton [14]

Answer:

.5? or 1/2

Step-by-step explanation:

i think its half, because the Y factors are going down by half.

i hope that kinda made sense.

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2 years ago
What is the area of the octagon?
Anna007 [38]

Answer:

A=2(1+2)a2

Step-by-step explanation:

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3 years ago
How many elements does A contains if it has 64 subsets​
Amanda [17]
<h3>Answer:  6</h3>

===========================================================

Explanation:

Rule: If a set has n elements in it, then it will have 2^n subsets.

For example, there are n = 3 elements in the set {a,b,c}. This means there are 2^n = 2^3 = 8 subsets. The eight subsets are listed below.

  1. {a,b,c} .... any set is a subset of itself
  2. {a,b}
  3. {a,c}
  4. {b,c}
  5. {a}
  6. {b}
  7. {c}
  8. { } ..... the empty set

Subsets 2 through 4 are subsets with exactly 2 elements.  Subsets 5 through 7 are singletons (aka sets with 1 element). The last subset is the empty set which is a subset of any set. You could use the special symbol \varnothing to indicate the empty set.

For more information, check out concepts relating to the power set.

-------------------

The problem is asking what value of n will make 2^n = 64 true.

You could guess-and-check your way to see that 2^n = 64 has the solution n = 6.

Another approach is to follow these steps.

2^n = 64\\\\2^n = 2^6\\\\n = 6

Which is fairly trivial.

Or you can use logarithms to solve for the exponent.

2^n = 64\\\\\text{Log}\left(2^n\right)=\text{Log}\left(64\right)\\\\n*\text{Log}\left(2\right)=\text{Log}\left(64\right)\\\\n=\frac{\text{Log}\left(64\right)}{\text{Log}\left(2\right)}\\\\n\approx\frac{1.80617997398389} {0.30102999566399} \ \text{ ... using base 10 logs}\\\\n\approx5.99999999999983\\\\

Due to rounding error, we don't land exactly on 6 even though we should.

5 0
2 years ago
Find the solution set 7x^2-9x-10=0
vitfil [10]

Answer:

x = -5/7, 2

Step-by-step explanation:

Step 1: Factor

(5x + 7)(x - 2) = 0

Step 2: Find <em>x </em>roots

5x + 7 = 0

x = -5/7

x - 2 = 0

x = 2

5 0
3 years ago
Read 2 more answers
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