What technology would it take to make a balloon that doesn't pop?

Which of these is a way that a doctor can examine a patient?

SIZIF [17.4K]

Answer:

D. all the above

Explanation:

because doctor uses stethoscope to listen patients heart, he also used hammer to check patients reflexes and also doctor has to listen to the patient.

5 0

3 years ago

The following checksum formula is widely used by banks and credit card companies to validate legal account numbers: d0 + f(d1) +

Aleksandr [31]

Answer:

Here is the JAVA program:

import java.util.Scanner; //to import Scanner class

public class ISBN

{ public static void main(String[] args) { // start of main() function body

Scanner s = new Scanner(System.in); // creates Scanner object

//prompts the user to enter 10 digit integer

System.out.println("Enter the digits of an ISBN as integer: ");

String number = s.next(); // reads the number from the user

int sum = 0; // stores the sum of the digits

for (int i = 2; i <= number.length(); i++) {

//loop starts and continues till the end of the number is reached by i

sum += (i * number.charAt(i - 1) ); }

/*this statement multiplies each digit of the number with i and adds the value of sum to the product result and stores in the sum variable*/

int remainder = (sum % 11); // take mod of sum by 11 to get checksum

if (remainder == 10)

/*if remainder is equal to 10 adds X at the end of given isbn number as checksum value */

{ System.out.println("The ISBN number is " + number + "X"); }

else

// displays input number with the checksum value computed

{System.out.println("The ISBN number is " + number + remainder); } } }

Explanation:

This program takes a 10-digit integer as a command line argument and uses Scanner class to accept input from the user.

The for loop has a variable i that starts from 2 and the loop terminates when the value of i exceeds 10 and this loop multiplies each digit of the input number with the i and this product is added and stored in variable sum. charAt() function is used to return a char value at i-1.

This is done in the following way: suppose d represents each digit:

sum=d1 * 1 + d2 * 2 + d3 * 3 + d4 * 4 + d5 * 5 + d6 * 6 + d7 * 7 + d8 * 8 + d9 * 9

Next the mod operator is used to get the remainder by dividing the value of sum with 11 in order to find the checksum and stores the result in remainder variable.

If the value of remainder is equal to 10 then use X for 10 and the output will be the 10 digits and the 11th digit checksum (last digit) is X.

If the value of remainder is not equal to 10, then it prints a valid 11-digit number with the given integer as its first 10 digits and the checksum computed by sum % 11 as the last digit.

8 0

3 years ago

Consider the code fragment below (with nested loops). int sum = 0;for (int i = 1; i < 5; i++) for (int j = 1; j <= i; j++)

sammy [17]

Answer:

Option d is the correct answer for the above question.

Explanation:

The first loop of the program has a second loop and then the statement. In this scenario, the second loop executes for the value of the first loop and the statement executes for the value of the second loop.
The first loop executes 4 times, Then the second loop or inner loop executes n times for the n iteration of the first loop, for example, 1 time for the first iteration of the first loop, 2 times for the second iteration of the first loop and so on.
Then the inner loop executes (1+2+3+4) iteration which gives the result 10 iterations.
The sum initial value is 0 and the "sum++", increase the value of the sum by 1.
So the value of the sum becomes 10 after completing 10 iterations of the inner for loop.
Hence the 10 will be the output. So the Option d is the correct answer while the other is not.

3 0

3 years ago

When creating a presentation in Libre Office Impress, where does the editing of slides take place?

kondor19780726 [428]

The Canterbury Tales, written towards the end of the fourteenth century by Geoffrey Chaucer, is considered an estates satire because it effectively criticizes, even to the point of parody, the main social classes of the time. These classes were referred to as the three estates, the church, the nobility, and the peasantry, which for a long time represented the majority of the population.

4 0

3 years ago

Prompt the user to input five pairs of numbers: A player's jersey number (0 - 99) and the player's rating (1 - 9). Store the jer

tiny-mole [99]

Answer:

import java.util.Scanner;
public class Main {
public static void main (String [] args) {
int jersey_num [] = new int[5];
int rating [] = new int[5];
Scanner inStream = new Scanner(System.in);
for(int i=0; i < 5; i++){
System.out.print("Enter player " + (i+1) + "'s jersey number:");
jersey_num[i] = inStream.nextInt();
System.out.print("Enter player " + (i+1) + "'s rating:");
rating[i] = inStream.nextInt();
}
System.out.println("ROSTER");
for(int j=0; j < 5; j++){
System.out.println("Player " + (j+1) + "-- Jersey number: " + jersey_num[j] + ", Rating: " + rating[j]);
}
}
}

Explanation:

The solution code is written in Java. Firstly create two array, jersey_num and rating, with int type. This is to hold the five pairs of numbers input by user (Line 6 -7).

Next, create a for loop that run for 5 iterations and in each iteration prompt user to input jersey number and rating (Line 11 -17). The input number and rating will be set to the array, jersey_num and rating, respectively.

Next, print the title "Roster" (Line 19).

Create another for loop to display the five input pair of values (Line 21 - 23).

3 0

3 years ago