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3 years ago

Mr. Lewis designed a circular walkway in

Mathematics

1 answer:

NARA [144]3 years ago

8 0

Answer:

The diameter is equal to the circumference divided by the number pi

Step-by-step explanation:

we know that

The circumference of the circular walkway is equal to

$C=\pi D$

where

D is the diameter

we have

$D=6\ ft$

substitute

$C=\pi (6)$

$C=6\pi\ ft$

Divide the diameter by the circumference

$\frac{D}{C}=\frac{6}{6\pi}$

$\frac{D}{C}=\frac{1}{\pi}$

$D=\frac{C}{\pi}$

The diameter is equal to the circumference divided by the number pi

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Whats the product of 6 and q

nevsk [136]

Answer:

6q or 6 * q

Step-by-step explanation:

As you do not know what the value of the variable q is, you are essentially changing it from word form to expression form.

"product" in math means multiply, so you are multiplying 6 with q.

6q is your answer.

7 0

3 years ago

Read 2 more answers

Please can you give me help with answers. Thanks

Margaret [11]

1) 110+30+a = 180
a = 180-140 = 40
Obtuse angled triangle

2) 50+50+C = 180
C=180-100 =80
Acute angled triangle

3) 45+45+b =180
b =180-90 = 90
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4) 45+60+C = 180
C = 180-105 =75
Acute angled triangle

5) 94+47+b =180
b = 180-141=39

Obtuse angled triangle

6)81+53+a = 180
a =180-134 = 46

Acute angled triangle

7) 38+45+b =180
b = 180-83 =97
Obtuse angled triangle

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2 years ago

What is the perpendicular slope of the line shown below?

malfutka [58]

That slope appears to be 4/6 or 2/3.

The perpendicular slope will have the opposite sign and be the reciprocal.

The perpedicular slope is –3/2.

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2 years ago

Which expression is equivalent to (4^−3)^−6? 1. 4^-18 2. 4^18 3. 4^-9 4. 4^3

malfutka [58]

Answer:

4^18

Step-by-step explanation:

4^18 = 2^36

(4^−3)^−6? = 2^36

Please visit: https://youtu.be/_0Ft9HdNg5c

Thanks.

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3 years ago

WILL MARK BRAINLIEST!

Artist 52 [7]

Answer:

Following are the responses to the given points:

Step-by-step explanation:

Dilation implies the triangle $\Delta XYZ$ stretched through the factor "2".

$m\angle Y = m\angle C = 90^{\circ} \leftarrow given \\\\$

right triangles:

$\Delta XYZ and \Delta ACB \\\\\angle X \cong \angle A \leftarrow given\\\\$

complementary angles:

$\angle X \ and\ \angle Z$

$m\angle Z = 90^{\circ} - m\angle X \\\\$

complementary angles:

$\angle A \ and\ \angle B$

$m\angle B = 90^{\circ} - m\angle A \\\\\therefore \\\\ \angle Z \cong \angle B \\\\\Delta XYZ \sim \Delta ACB \\\\$

Same triangles: proportional side are corresponding, congruence angles are respective.

$\sin \angle X = \frac{5}{5.59} \leftarrow given \\\\\sin\angle X = \frac{YZ}{XY} \\\\YZ = 5 (units) \rightarrow leg in \Delta XYZ \\\\XZ = 5.59 (units) \rightarrow hypotenuse \ in\ \Delta XYZ\\\\$

Calculating the length of leg XY:

$XY = \sqrt{((5.59)^2 - 52)} \cong 2.4996 (units)\\\\\frac{CB}{YZ} = 2 \leftarrow given \\\\CD = 2YZ = 2 \times 5 = 10 \ (units)\\\\\frac{AC}{XY} = 2 \leftarrow \ given\\\\AC = 2XY \cong 2 \times 2.4996 \cong 4.999\ (units)\\\\$

3 0

2 years ago