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3 years ago

Mr. Lewis designed a circular walkway in

Mathematics

1 answer:

NARA [144]3 years ago

8 0

Answer:

The diameter is equal to the circumference divided by the number pi

Step-by-step explanation:

we know that

The circumference of the circular walkway is equal to

$C=\pi D$

where

D is the diameter

we have

$D=6\ ft$

substitute

$C=\pi (6)$

$C=6\pi\ ft$

Divide the diameter by the circumference

$\frac{D}{C}=\frac{6}{6\pi}$

$\frac{D}{C}=\frac{1}{\pi}$

$D=\frac{C}{\pi}$

The diameter is equal to the circumference divided by the number pi

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If 3x - 2y = 9 , 27x³- 8y³= 1377 , prove that xy = 4 plzz answer this question...

solniwko [45]

Step-by-step explanation:

Here we are given that , the Value of

$3x - 2y = 9$
$27x^3 - 8y^3 = 1377$

And we need to find the prove that ,

$xy = 4$

We know a identity as ,

$(a-b)^3 = a^3-b^3-3ab(a-b)$

On cubing both sides of the given equation,

$(3x-2y)^3 = 9^3$

Simplify and then substitute ,

$27x^3-8y^3 -3(3x)(2y)(3x-2y ) = 729$

$1377 - 18xy (9) = 729$

$162xy = 1377-729$

$xy =\dfrac{648}{162}$

$xy = 4$

Hence Proved !

8 0

3 years ago

At the end of dinner, equivalant amounts of lasagna in two pans were left.

Oksanka [162]

2/4+2/4 or 1/2+1/2

if there is 2/4 in one pan and 1/2 in another 2/4=1/2

8 0

3 years ago

How do you simplify that question? For algebra 1.

motikmotik

$\left( \sqrt{x^{-3}} \right)^5 = \left( \sqrt{ \frac{1}{x^3} } \right)^5= \frac{1}{ (\sqrt{x^3})^5 } = \frac{1}{ \sqrt{x^{15}} } = \frac{1}{x^7 \sqrt{x} }$

Explanation for the last step:
$\sqrt{x^{15}}= \sqrt{x^{14}*x}= \sqrt{x^{14}}* \sqrt{x} =x^{ \frac{14}{2} }* \sqrt{x} =x^7 \sqrt{x}$

7 0

3 years ago

2(3x – 1) = –6x – 2 can someone help

Gnom [1K]

Let's solve your equation step-by-step.

2(3x−1)=−6x−2

Step 1: Simplify both sides of the equation.

2(3x−1)=−6x−2

(2)(3x)+(2)(−1)=−6x+−2(Distribute)

6x+−2=−6x+−2

6x−2=−6x−2

Step 2: Add 6x to both sides.

6x−2+6x=−6x−2+6x

12x−2=−2

Step 3: Add 2 to both sides.

12x−2+2=−2+2

12x=0

Step 4: Divide both sides by 12.

12x/12= 0/12

x=0

Answer:

x=0

HOPE THIS HELPS!!! :)

5 0

2 years ago

Its about differention

nika2105 [10]

Had -9-x^2
———
x^2

adh (-9-x^2)
——————-
x^2

-9adh-adhx^2
———————
x^2

9adh+adhx^2
- ———————
x^2

Hope this helps

6 0

2 years ago