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TEA [102]
3 years ago
11

A scientist is comparing that outer layer of an onion cell to the outer layer of a human cell what is unique about the outer lay

er of the onion cell compared to the skin cell
Biology
2 answers:
Ira Lisetskai [31]3 years ago
5 0
<span>The function of a cell wall has the same function of the cell membrane; it protects the cell. Cell wall is made up of cellulose that is only present in plant cells. Cellulose is a sugar that has a sheet like structural carbohydrate. It is rigid that is used for support and provides protection to the plant cell from damage. They cannot be dissolved in water. An example is if you eat food that contains mostly of leaves. You will observe that you will eliminate the same material as when you it. That is because our human body does not have the enzyme that dissolves the cellulose.</span>
EastWind [94]3 years ago
3 0

Answer;

Unlike animal cells (such as cheek cells) the cell wall of an onion and other plants are made up of cellulose, which protects the cell and maintains its shape.

Explanation;

-The main structural differences between plant and animal cells lie in a few additional structures found in plant cells. These structures include: chloroplasts, the cell wall, and vacuoles.

-Plants cells have cell walls and other structures that differ from those of animals. Animal cells do not have cell walls and have different structures than plant cells. Plants have either no or very basic ability to sense.

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In flies dumpy wings and ebony bodies are each mutations recessive to wild type, and you expect them to behave in a Mendelian fa
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Answer:

See the answers below

Explanation:

Assuming that D (d) represents the allele for wing type and E (e) represents the allele for body type, crossing DdEe with DdEe will yield the following offspring according to the Punnet's square (see the attached image):

(a) <em>9/16 D_E_  wild type </em>

<em>     3/16 D_ee  wild wing, ebony body</em>

<em>     3/16 ddE_ dumpy wing, wild body</em>

<em>     1/16 ddee dumpy wing, ebony body</em>

(b) Chi square X^2 = \frac{(O - E)^2}{E}, where O = observed frequency and E = expected frequency.

Phenotype                O                  E                                           X^2

Wild type                 473          9/16 x 830 =  466.875     \frac{(473 - 466.875)^2}{466.875} = 0.08

wild w/ebony b      156          3/16 x 830 = 155.625       \frac{(156 - 155.625)^2}{155.625} =  0.0009

Dumpy w/wild b     149          3/16 x 830 = 155.625      \frac{(149 - 155.625)^2}{155.625} = 0.28

dumpy w/ebony b  52            1/16 x 830 = 51.875        \frac{(52 - 51.875)^2}{51.875} = 0.0003

Total X^2 = 0.3612

Degree of freedom = 4 - 1 = 3

Tabulated value of X^2 (0.05)= 7.815

(c) <em>Since the calculated Chi square value is less than the tabulated value, we conclude that the observed outcome agrees with the expected outcome and that the cross followed the standard Mendelian pattern.</em>

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