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3 years ago

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A lit house worker is tracking a boat that is 2.1 km south from her. She is also tracking a boat that is 3.5 km from the tower l

ocated 70 degrees east of north. To the nearest tenth of a kilometer, how far apart are the two boats?

1 answer:

vlada-n [284]3 years ago

8 0

Answer:

21.5 km

Step-by-step explanation:

We have to find the distance between two boat

We are given that

AC=2.1 km

BC=3.5 km

We have to find BC

The angle between two boat =110 degrees

Using cosine law

BC= $\sqrt{(2.1)^2+(3.5)^2-2\cdot(2.1)\cdot(3.5)cos 110}$

BC= $\sqrt{4.41+12.25+ 2\cdot2.1\times3.5cos 70$

BC= $\sqrt{4.41+12.25+9.3051}$

BC=21.507 km

Hence, the distance between two boat is 21.5 km

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