Question

A lit house worker is tracking a boat that is 2.1 km south from her. She is also tracking a boat that is 3.5 km from the tower located 70 degrees east of north. To the nearest tenth of a kilometer, how far apart are the two boats?

Answer 1

Answer:

21.5 km

Step-by-step explanation:

We have to find the distance  between two boat

We are given that

AC=2.1 km

BC=3.5 km

We have to find BC

The angle between two boat =110 degrees

Using cosine law

BC=$\sqrt{(2.1)^2+(3.5)^2-2\cdot(2.1)\cdot(3.5)cos 110}$

BC=$\sqrt{4.41+12.25+ 2\cdot2.1\times3.5cos 70$

BC=$\sqrt{4.41+12.25+9.3051}$

BC=21.507 km

Hence, the distance between two boat is 21.5 km