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3 years ago

7

Mathematics

2 answers:

Rus_ich [418]3 years ago

7 0

Answer:

something.....................

ValentinkaMS [17]3 years ago

6 0

Answer:

sry sry I'm in a hurry..........

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Can someone help please?

d1i1m1o1n [39]

wow hows college going any tips for me when i go

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2 years ago

Amy joins a meal delivery service. Each family meal is $15, and there is a monthly flat shipping fee of $20. If Amy orders eight

8090 [49]

Answer: 140$

Step-by-step explanation: 15$ times 8 meals plus 20 dollar fee eaquals 140$

4 0

2 years ago

A city-wide gardening club is up of men, women and children in the ratio 5:4:11.

Sever21 [200]

Answer:

Women: 448 Men: 560 Children: 1232

Step-by-step explanation:

5+4+11 = 20/2240 = 112

Women = 4 x 112 = 448

Men = 5 x 112 = 560

Children = 11 x 112 = 1232

Total = 1232 + 560 +448 = 2240

3 0

3 years ago

What’s the name of each quadrilateral and the answer

OleMash [197]

A) rhombus
b) trapezoid
c) square
d) rectangle
e) parallelogram
f) trapezoid
g) a parallelogram has 4 sides. The two opposite sides are always parallel.
A trapezoid has 4 sides. Only two opposite sides are parallel. The other two sides are not parallel.
h) a square has angles that must be 90degree big. A rhombus doesn’t.

7 0

3 years ago

Please help solve for x..

aalyn [17]

Answer:

x = 1 or x = -1

Step-by-step explanation:

Given equation:

$x^{100}-4^x \cdot x^{98}-x^2+4^x=0$

Factor out -1:

$\implies -1(-x^{100}+4^x \cdot x^{98}+x^2-4^x)=0$

Divide both sides by -1:

$\implies -x^{100}+4^x \cdot x^{98}+x^2-4^x=0$

Rearrange the terms:

$\implies 4^x \cdot x^{98}-4^x-x^{100}+x^2=0$

$\textsf{Apply exponent rule} \quad a^{b+c}=a^b \cdot a^c \quad \textsf{to }x^{100}:$

$\implies 4^x \cdot x^{98}-4^x-x^{98}x^2+x^2=0$

Factor the first two terms and the last two terms separately:

$\implies 4^x(x^{98}-1)-x^2(x^{98}-1)=0$

Factor out the common term $(x^{98}-1)$ :

$\implies (4^x-x^2)(x^{98}-1)=0$

<u>Zero Product Property</u>: If a ⋅ b = 0 then either a = 0 or b = 0 (or both).

Using the <u>Zero Product Property</u>, set each factor equal to zero and solve for x (if possible):

$\begin{aligned}x^{98}-1 & = 0 & \quad \textsf{or} \quad \quad4^x-x^2 & = 0 \\x^{98} & =1 & 4^x & = x^2 \\x & = 1, -1 & \textsf{no}& \textsf{ solutions for } x \in \mathbb{R}\end{aligned}$

Therefore, the solutions to the given equation are: x = 1 or x = -1

Learn more here:

brainly.com/question/27751281

brainly.com/question/21186424

3 0

1 year ago