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2 years ago

What is the volume of the box? A) 4 1/2 ft B)72 ft C)18 ft D)1 1/8 ft

Mathematics

1 answer:

defon2 years ago

8 0

Answer:

18 ft

Step-by-step explanation:

the sides are 12 cubes . There are six of those 12 cubed sides. 12x6=72. 72x.25=18

18 is the answer

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State whether f is a function

Alenkinab [10]

<h2>Answer:</h2>

$y=\pm (\frac{x}{6})^{\frac{1}{4}} \ is \ not \ a \ function$

<h2>Step by step solution:</h2>

A function $f$ from a set $A$ to a set $B$ is a relation that assigns to each element $x$ in the set $A$ exactly one element $y$ in the set $B$ . The set $A$ is the domain (also called the set of inputs) of the function and the set $B$ contains the range (also called the set of outputs). On the other hand, a function has an inverse function if and only if passes the Horizontal Line Test for Inverse Functions. This test tells us that a function $f$ has an inverse function if and only if there is no any horizontal line that intersects the graph of $f$ at more than one point. So the function is called one-to-one. The graph of $f$ is shown below. As you can see, this function does not pass the Horizontal Line Test, therefore the inverse is not a function. However, let's find $f^-{1}(x)$ :

$f(x)=6x^4 \\ \\ Substitute \ f(x) \ by \ y \\ \\ y=6x^4 \\ \\ Interchange \ x \ and \ y: \\ \\ x=6y^4 \\ \\ Solve \ for \ y: \\ \\ y^4=\frac{x}{6} \\ \\ Solving \\ \\y=\pm \sqrt[4]{\frac{x}{6}} \\ \\ \boxed{y=\pm \left(\frac{x}{6}\right)^{\frac{1}{4}}}$

and this is not a function because there are elements in the set of inputs that match with two elements in the set of outputs.

5 0

3 years ago

Read 2 more answers

A population grows with an annual growth rate of 16.5 % per year. (a) what is the monthly growth rate

Shtirlitz [24]

The monthly growth rate would be 16.5% divided by 12 which is 1.3%

8 0

3 years ago

Please help I need help

FinnZ [79.3K]

Answer:

its option 3;92667

Step-by-step explanation:

6 and 8 is 68 so 9 2667 its 92667

3 0

3 years ago

Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (

IrinaVladis [17]

Answer:

Low Q1 Median Q3 High

6 9 11 12.5 14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14 and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = $\dfrac{9+9}{2}$

median = $\dfrac{18}{2}$

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = $\dfrac{12+13}{2}$

Median = $\dfrac{25}{2}$

Median = 12.5

Low Q1 Median Q3 High

6 9 11 12.5 14

The interquartile range = Q3 - Q1

The interquartile range = 12.5 - 9

The interquartile range = 3.5

7 0

3 years ago

Challenge You have 2 different savings accounts. For Account A, the simple interest earned after 3 months is $1.60. For Account

const2013 [10]

Answer:

$1.28

Note for you:

I hope this helps!

Answer and Step-by-step explanation:

The computation is shown below;

As we know that

The simple interest is

Simple interest = Principal × rate × time

For Account A, the principal would be

2 = Principal × 3.2% × 3

So, the principal is $20.83

For account B, the principal would be

38.50 = Principal × 2.2% × 30

So, the principal is $58.33

Now the interest for both the accounts are as follows

For account 1

= $20.83 × 3.2%

= $0.67

And, for the account 2

= $58.33 × 2.2%

= $1.28

As it can be seen that the account 2 has the highest interest

The same is to be considered

4 0

2 years ago