Answer:
player1Wins = player1Losses = player2Wins = player2Losses = tieCount = 0
score1 = 10
score2 = 10
if score1>score2:
player1Wins=player1Wins+1
player2Losses=player2Losses+1
print("player1 wins")
elif score2>score1:
player2Wins=player2Wins+1
player1Losses=player1Losses+1
print("player2 wins")
else:
tieCount=tieCount+1
print("tie")
Explanation:
Since your indentation can not be understand what you give us, please try to do it as you see in the answer part.
Although it seems that this is a part of the code, it is normal that you get errors. However, since you keep track of the variables, it is better to initialize the variables that will keep the counts. Since initially, they are 0, you may set them as 0. Also, if you assign the values to the scores, probably you would not get any error. This way, you may test your code as I did.
Other than these, in the else part you do not need to write "score1=score2", because if score1 is not greater than score2 and if score2 is not greater than score1, this already implies that they are equal
Answer:
The correct answer to the following question is ACL name is the case sensitive.
Explanation:
ACL name is unique, alphanumeric and case sensitive that's why the router deals like the access_network, the ACCESS_NETWORK as it if they are the two separates ACL's.
That's why ACL always has the unique identities.
Answer:
The answer is "Option A".
Explanation:
This architecture is built upon an app feedback design model for sequential and concurrent systems, which is also known as an innovation for parallel programming, It also uses the networks for communication, and another option is not correct, that can be described as follows:
- Option B and Option C both are wrong because they can't produce structures and receives its data.
- In option D, It is wrong, because it can't publish the menus.
A. performance because a poetry reading is when a poem is read out loud to an audience.
