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MissTica
3 years ago
10

Find the interquartile range (IQR) of the data in the dot plot below.

Mathematics
2 answers:
adelina 88 [10]3 years ago
8 0

Answer:

2

Step-by-step explanation:

Arlecino [84]3 years ago
6 0
The answer is 2. If you were to make a box plot you’d subtract the second highest dot from the second lowest dot. That’s be your IQR.
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A $4,000.00 principal earns 5% interest, compounded annually. After 4 years, what is the balance in the account?
alukav5142 [94]
4000(1.05)⁴=$4862.03

6000(1+ .08/2)^35(2)=$93429.71

15450(.86)³=$9827.07
8 0
3 years ago
Read 2 more answers
The net of a square pyramid is shown
Wewaii [24]

Answer:

Option (D)

Step-by-step explanation:

Surface area of a square pyramid is determined from the formula,

Surface area = Area of the square base + 4(Area of one lateral triangular side)

Area of the base = (Side)²

                            = 8²

                            = 64 cm²

Area of one lateral triangle = \frac{1}{2}(\text{Base})(\text{Height})

                                             = \frac{1}{2}(8)(8)

                                             = 32 cm²

Therefore, surface area of the square pyramid = 64 + 4(32)

                                                                              = 64 + 128

                                                                              = 192 cm²

Therefore, Option (D) will be the correct option.

3 0
2 years ago
Scientists measure a bacteria sample in a petri dish
zimovet [89]

Answer:

to grow bacterial cultures

4 0
2 years ago
Solve the system by using a table. {-0.2x-0.3y=0.2 {0.4x-0.3y=1.4 a.)(2,2) b.) (2,-2) c.)(2,1) D.)(-2,2)
vitfil [10]
<span>2, -2, 0.2, 1.4 <<<----- answer (2,-2) </span>
5 0
3 years ago
Use quadratic formula to find both solutions to the quadratic equation given below . 3x^2-5x-1=0
Rudiy27

Answer:

x1=\frac{5+\sqrt{37}} {6}

x2=\frac{5-\sqrt{37}} {6}

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

3x^{2} -5x-1=0  

so

a=3\\b=-5\\c=-1

substitute in the formula

x=\frac{5(+/-)\sqrt{(-5)^{2}-4(3)(-1)}} {2(3)}

x=\frac{5(+/-)\sqrt{37}} {6}

x1=\frac{5+\sqrt{37}} {6}

x2=\frac{5-\sqrt{37}} {6}

8 0
3 years ago
Read 2 more answers
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