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cluponka [151]
3 years ago
12

Simplify 3(2f+6)+7thanks

Mathematics
1 answer:
Naya [18.7K]3 years ago
4 0

{Expand} 3(2f+6): 6f+18

6f+18+7

18+7=25

= 6f+25

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find the inner product for (3,5) x (4,-2) and state whether the vectors are perpendicular. a.1; no b.1;yes c.2; no d.2; yes
MakcuM [25]

Answer:

  c.  2; no

Step-by-step explanation:

The inner product is the sum of the products of corresponding vector components. It is a scalar value, not a vector value.

  (3, 5)·(4, -2) = (3)(4) +(5)(-2) = 12 -10 = 2

When the inner product is non-zero, the vectors are not perpendicular. (The yes answers with a non-zero value can be rejected out of hand.)

The appropriate choice is ...

  2; no

5 0
3 years ago
The numbers {0, −​1, ​1.9, √3​, ​15} are examples of what set of​ numbers?
atroni [7]
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3 years ago
Help please explain as simple as possible
Virty [35]
Short answer: (-8)^2 + 8  x  -8 = 0

Use PEMDAS

"Evaluate the expression" just means solve until you can't simplify anymore. You must solve it in a certain order according to PEMDAS: Parentheses, Exponents, Multiply, Divide, Add, Subtract.

What does the beginning of the expression look like? It is (-8)^{2}.

According to PEMDAS, you must solve what is in the parentheses *first*. But, since there is only a number (-8), there is nothing to solve for and you can move on to exponents.

The squared symbol, the little 2, means you have to square what is *inside* the parentheses. (-8)^{2} = 64, because -8 times itself is 64.

Next comes multiplication. Remember, we are not working from left to right. We must multiply the values on the far right before we do any adding, because multiplication comes *before* addition.

(64) + (8 times -8)

(64) + (-64)

Finally, we can add. In this case, because we are adding a negative number, we are really subtracting. 64 + -64 equals 0.
8 0
4 years ago
2(2x + 3)^2– 7(2x + 3) - 4
Lana71 [14]

Answer:

Solution in photo

Step-by-step explanation:

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3 years ago
F as a function of x is equal to the square root of quantity 6 x plus 9 , f as a function of x is equal to the square root of qu
Elis [28]

Answer:

A. \sqrt{6x+9} +\sqrt{6x-9}

Step-by-step explanation:

We are given the functions f(x) and g(x) as,

f(x)=\sqrt{6x+9}

g(x)=\sqrt{6x-9}

It is required to find the function ( f+g ) i.e. ( f+g ) (x)

So, (f+g)(x)=f(x)+g(x)

i.e. (f+g)(x)=\sqrt{6x+9}+\sqrt{6x-9}

Hence, we get that (f+g)(x)=\sqrt{6x+9}+\sqrt{6x-9}.

So, the first option is correct.

4 0
3 years ago
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