Question

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Answer 1

The mean score when the outlier removed is 8.

Step-by-step explanation:

The number of quiz scores were 15.

The scores are 3,6,7,7,7,7,8,8,8,8,8,9,9,10,10.

That is he scored 4 times 7, 5 times 8, 2 times 9 and 10.

The mean $m=\frac{sum of all the values}{total number of the values}$.

Here $m=\frac{3+6+7+7+7+7+8+8+8+8+8+9+9+10+10}{15}$.

$m=\frac{115}{15}$.

m= 7.67.

If outlier 3 is removed then remaining score are 6,7,7,7,7,8,8,8,8,8,9,9,10,10.

The number of quiz scores will be 14

The mean $m=\frac{sum of all the values}{total number of the values}$.

Here $m=\frac{6+7+7+7+7+8+8+8+8+8+9+9+10+10}{14}$.

$m=\frac{112}{14}$.

m= 8.

The mean score when the outlier removed is 8.