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Mekhanik [1.2K]
3 years ago
8

One ticket costs $15.45. Three tickets would cost?

Mathematics
1 answer:
Troyanec [42]3 years ago
8 0
46.35 is the answer
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Can someone help me with this?​
Sveta_85 [38]

Answer:

45n

Step-by-step explanation:

5 0
3 years ago
Use the method of symmetry to find the extreme value of each quadratic function and the value of x for which it occurs.
-BARSIC- [3]

Answer:

  • See below

Step-by-step explanation:

The x-intercepts are the points with y- coordinate of 0

  • (x - 3)(x + 8) = 0
  • x - 3 = 0 or x + 8 = 0
  • x = 3 or x = - 8

a) x-intercepts are

  • 3 and - 8

b) midpoint of x-intercepts is

  • (3 - 8)/2 = - 5/2 = - 2.5

c) The extheme value has x- coordinate of - 2.5 and y- coordinate

  • (-2.5 - 3)(- 2.5 + 8) = (-5.5)(5.5) = - 30.25

d) f(- 2.5) = - 30.25

3 0
2 years ago
The sum of the first 150 negative integers is represented using the expression
Leona [35]

Answer:

\large\boxed{-11,325}

Step-by-step explanation:

First simplify:

-1-(n-1)=-1-n-(-1)=-1-n+1=-n

Therefore we have:

\sum\limits_{n=1}^{150}[-1-(n-1)]=\sum\limits_{n=1}^{150}(-n)=(-1)+(-2)+(-3)+...+(-150)\\\\-1,\ -2,\ -3,\ -4,\ ...,\ -150-\text{it's the arithmetic sequence}\\\text{with the common difference d = -1.}\\\\\text{The formula of a sum of terms of an arithmetic sequence:}\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\\text{Substitute}\ n=150,\ a_1=-1,\ a_n=-150:\\\\S_{150}=\dfrac{-1+(-150)}{2}\cdot150=(-151)(75)=-11,325

8 0
3 years ago
5/7(14-21x)=115<br> what is the answer?
Elan Coil [88]

Answer:

-7

Step-by-step explanation:

3 0
3 years ago
A group of children, adults, and senior citizens attended three different art exhibits that have different ticket prices for eac
jok3333 [9.3K]

Answer:

Option D) c = 100, a = 50, s = 20

Step-by-step explanation:

we have

6c + 7a + 2s = 990  -----> equation A

3c + 3a + 4s = 430  -----> equation B

2c + 4a + 4s = 480 ----> equation C

Isolate variable s in equation A

2s = 990 -6c-7a  

s=495-3c-3.5a -----> equation D

Substitute equation D in equation B and in equation C

3c + 3a + 4(495-3c-3.5a) = 430

3c + 3a +1,980-12c-14a= 430

-9c-11a=-1,550 -----> equation E

2c + 4a + 4(495-3c-3.5a) = 480

2c+4a+1,980-12c-14a=480

-10c-10a=-1,500 -----> 10c+10a=1,500 -----> equation F

Solve the system of equations E and F by graphing

using a graphing tool

Let

The variable c -----> the x-axis

The variable a ----> the y-axis

The solution is the point (50,100)

see the attached figure

so

c=50, a=100  

Find the value of s

s=495-3(50)-3.5(100)=-5 -----> is not make sense

therefore

Let

The variable c -----> the y-axis

The variable a ----> the x-axis

The solution is the point (50,100)

so

a=50, c=100  

Find the value of s

s=495-3(100)-3.5(50)=20

therefore

The solution is

c=100,a=50,s=20

7 0
4 years ago
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