Please help me?
2 answers:
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Answer:
C
Step-by-step explanation:
Given:
Number of samples, n = 100
let number of sample that favoured candidate A be x = 80
probability, p' = x/n = 80/100 = 0.8
probability, p for significance = 75% = 0.75
Using Z-proportion test statistics, we have
Z =
Substituting the values, we have
Z =
Z = 0.05 / 0.0433 = 1.1547
The p-value is
P(Z>1.1547) = 1 - P(Z≤1.1547)
Checking the Z-score table, P(Z≤1.1547) = 0.8789
Hence, we have 1 - 0.8789
= 0.1241
Hence, the p-value is greater than 0.05, so we cannot say it is very significant.
Hence, the population in favour of candidate A is not significantly greater than 75%
Answer:
-88 mph
Step-by-step explanation:
We can use the relation ...
time = distance/speed
to compare the times in the two directions.
The wind speed is -88 miles per hour.
_____
The problem statement tells us the travel is slower <em>with</em> the wind than <em>against</em> the wind. Hence "with the wind" must be subtracting from the net speed. That is, the wind speed is negative.