so, we know both the rectangular prism and the cylinder got filled up to a certain height each, the same height say "h" cm.
we know the combined volume of both is 80 cm³, so let's get the volume of each, sum them up to get 80 then.
![\bf \stackrel{\stackrel{\textit{volume of a}}{\textit{rectangular prism}}}{V=Lwh}~~ \begin{cases} L=length\\ w=width\\ h=height\\[-0.5em] \hrulefill\\ L=4\\ w=2\\ \end{cases}~\hspace{2em}\stackrel{\textit{volume of a cylinder}}{V=\pi r^2 h}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=1 \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Cstackrel%7B%5Ctextit%7Bvolume%20of%20a%7D%7D%7B%5Ctextit%7Brectangular%20prism%7D%7D%7D%7BV%3DLwh%7D~~%20%5Cbegin%7Bcases%7D%20L%3Dlength%5C%5C%20w%3Dwidth%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20L%3D4%5C%5C%20w%3D2%5C%5C%20%5Cend%7Bcases%7D~%5Chspace%7B2em%7D%5Cstackrel%7B%5Ctextit%7Bvolume%20of%20a%20cylinder%7D%7D%7BV%3D%5Cpi%20r%5E2%20h%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D1%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
76.0 would be your answer
Answer: -1.5
Step-by-step explanation:
4/5n – 1/5 = 2/5n
Add 1/5 to both sides
4/5n = 2/5n + 1/5
Subtract 2/5n from both sides
2/5n = 1/5
Divide both sides by 2/5
n = 1/2
Answer:
The correct option is:
y - x = -4
Step-by-step explanation:
The graphed equation is:
y = x - 4
The equation which will have infinite number of solution should overlap the graphed equation at infinity points.
It is only possible when both the equations are exactly same.
Consider the line given:
y - x = -4
Rearrange the equation:
y = x - 4
Thus, it is the same as the first equation.
Verify for point (0,-4)
y - x = -4
-4 - 0 = -4
-4 = -4
Proved.
Verify for point (4,0)
y - x = -4
0 - 4 = -4
0 = -4+4
0 = 0
Proved
