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bija089 [108]
3 years ago
5

Can you help me please for this ^^

Mathematics
2 answers:
patriot [66]3 years ago
5 0
You would need to bring 17 school buses because if you divide 842 divided by 48 would be 17.5. And you would halfway fill up 17 buses so all you need is 17 buses to take with you. Hope this helps :)
Stels [109]3 years ago
4 0
Sorry it's wonky but I hope you get it if you don't I can explain again

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Chelsea and her family are taking a road trip. they leave their home in flowery branch Georgia and drive to Nashville which is 1
sukhopar [10]

(x,y) ... (X-163, Y+125) Which ever direction it is, you apply it to the rule.

7 0
3 years ago
Determine the value of a if one solution to the quadratic equation is x equals 5 + 3/2 I
Sindrei [870]

The value of a is \frac{-9}{4}

Step-by-step explanation:

<u>1. Determine the other solution of x</u>

If one value is 5 + \frac{3}{2} then the other value is 5 - \frac{3}{2}

<u>2. Use reverse technique to find the equation</u>

(5 + \frac{3}{2}) (5 - \frac{3}{2}) = 0

25 - \frac{-15}{2} + \frac{15}{2} - \frac{9x^{2} }{4} = 0

- \frac{9x^{2} }{4} + 25 = 0

<u>3. The equation is</u> - \frac{9x^{2} }{4} + 25 = 0

<u>4. Find the value of a</u>

a is the number with the variable x^{2} therefore it is - \frac{9}{4}

Keyword: quadratic equation, solution

Learn more about quadratic equation at

  • brainly.com/question/4460262
  • brainly.com/question/1332667

#LearnwithBrainly

8 0
3 years ago
Can we obtain a diagonal matrix by multiplying two non-diagonal matrices? give an example
polet [3.4K]
Yes, we can obtain a diagonal matrix by multiplying two non diagonal matrix.

Consider the matrix multiplication below

\left[\begin{array}{cc}a&b\\c&d\end{array}\right]   \left[\begin{array}{cc}e&f\\g&h\end{array}\right] =  \left[\begin{array}{cc}a e+b g&a f+b h\\c e+d g&c f+d h\end{array}\right]

For the product to be a diagonal matrix,

a f + b h = 0 ⇒ a f = -b h
and c e + d g = 0 ⇒ c e = -d g

Consider the following sets of values

a=1, \ \ b=2, \ \ c=3, \ \ d = 4, \ \ e=\frac{1}{3}, \ \ f=-1, \ \ g=-\frac{1}{4}, \ \ h=\frac{1}{2}

The the matrix product becomes:

\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}\frac{1}{3}&-1\\-\frac{1}{4}&\frac{1}{2}\end{array}\right] = \left[\begin{array}{cc}\frac{1}{3}-\frac{1}{2}&-1+1\\1-1&-3+2\end{array}\right]= \left[\begin{array}{cc}-\frac{1}{6}&0\\0&-1\end{array}\right]

Thus, as can be seen we can obtain a diagonal matrix that is a product of non diagonal matrices.
8 0
3 years ago
Read 2 more answers
Help which graph describes exponential decay
DIA [1.3K]

Answer:

Graph 2.

Step-by-step explanation:

The graph is decreasing.

Hope this helps!

If not, I am sorry.

6 0
2 years ago
What is the decimal expansion of the following fraction?
pickupchik [31]
You haven't shared a fraction.  Please do that next time.

I checked and have found that 0.045 repeating over the 4 and 5 is equivalent to 1/22.  Try dividing 1 by 22 to verify this.

So I infer that the fraction you haven't yet shared is 1/22.
5 0
3 years ago
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