For circumference it’s 12x3.14= 37.68
10(0.5x + 6) = 8
5x + 60 = 8
5x = 8 - 60
5x = -52
x = -52/5
x = -10.4
Answer: Answer is: 14/209
Step-by-step explanation: Divide the first expression by the second one.
Second Answer: 1262.28571429
I think you're asking if it's possible to have a cube root, fifth root, 7th root, etc of a number as a solution to f(x). The answer is yes it's possible.
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Example:
f(x) = x^3 - 29
This function has one real-number root of
(cube root of 29) and the other two roots are complex or imaginary roots.