3 years ago

Help pls will give brainliest

Mathematics

1 answer:

Tomtit [17]3 years ago

3 0

Answer:

1) AB

2) BC

3) AC

ABC

4) PA and OH

5) SO and CP

6) CA and SH

(I know I already answered this, but..........)

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Jimmie graphs a quadratic function and finds that its zeros are at x=2 and x=3. Which function could Jimmie have graphed?

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The function Jammie graphed is $x^2-5x+6=0$

Step-by-step explanation:

The zeros of quadratic function are at x=2 and x=3

We can write them as:

$x-2=0\,\,and\,\,x-3=0\\or\\(x-2)(x-3)=0$

Multiplying them

$(x-2)(x-3)=0\\x(x-3)-2(x-3)=0\\x^2-3x-2x+6=0\\x^2-5x+6=0$

So, The function Jammie graphed is $x^2-5x+6=0$

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