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Alik [6]
3 years ago
13

Help pls will give brainliest

Mathematics
1 answer:
Tomtit [17]3 years ago
3 0

Answer:

1) AB

2) BC

3) AC

ABC

4) PA and OH

5) SO and CP

6) CA and SH

(I know I already answered this, but..........)

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Umm F soooo R me I need E help N with D this S
DiKsa [7]

12*12^3+2

12*1728+2

20736+2

20738

7 0
3 years ago
Read 2 more answers
What is the area of a trapezoid that has bases of 1 1/4 feet and 14 inches and a height of 3 inches? 43.5 in. 2 87 in. 2 22.9 in
PolarNik [594]
The area of a trapezoid is the average of the bases times the height, mathematically:

A=h(b1+b2)/2, in this case:

A=3(1.25ft(12in/ft)+14)/2

A=3(29)/2

A=43.5 in^2


4 0
3 years ago
What is the quotient of a number and five increased by four is sixteen.
mr_godi [17]
16-4=12

12x5=60

I'm putting together assumptions as this isn't really clear to me, I apologize.
4 0
4 years ago
Y=-1/3x^2-4x-5 in vertex form
grigory [225]

Answer:

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

Step-by-step explanation:

Given function:

Y=-\frac{1}{3}x^2-4x-5

We need to find the vertex form which is.,

y=a(x-h)^2+k

where (h,k) represents the co-ordinates of vertex.

We apply completing square method to do so.

We have  

Y=-\frac{1}{3}x^2-4x-5

First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

-3\times Y=-3\times\frac{1}{3}x^2-(-3)\times4x-(-3)\times 5

-3Y=x^2+12x+15

Isolating x^2 and x terms on one side.

Subtracting both sides by 15.

-3Y-15=x^2+12x-15-15

-3Y-15=x^2+12x

In order to make the right side a perfect square trinomial, we will take half of the co-efficient of x term, square it and add it both sides side.  

square of half of the co-efficient of x term = (\frac{1}{2}\times 12)^2=(6)^2=36

Adding 36 to both sides.

-3Y-15+36=x^2+12x+36

-3Y+21=x^2+12x+36

Since x^2+12x+36 is a perfect square of (x+6), so, we can write as:

-3Y+21=(x+6)^2

Subtracting 21 to both sides:

-3Y+21-21=(x+6)^2-21

-3Y=(x+6)^2-21

Dividing both sides by -3.

\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

8 0
4 years ago
I will give brainiest to whoever answers correctly !! Someone smart please help me !!!
oksano4ka [1.4K]
Try This answer 305.5
6 0
3 years ago
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