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riadik2000 [5.3K]

3 years ago

13

How to write 12,375,003 in expanded form

1 answer:

icang [17]3 years ago

6 0

Twelve million threehundred and seventy five thousand ans three

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Compute the probability of the event E1 that Bob wins in a duel against Eve alone, assuming he shoots first. (Hint: Let x be the

skad [1K]

Answer: Hello your question is incomplete attached below is the missing

n ( 1 + n )

Step-by-step explanation:

P( Bob hits target ) = 1/3

P( Eve hits target ) = 2/3

P( Carol hits target ) = 1

<u>Compute the P that Bob wins in a duel against Eve alone</u>

P(Bob hits the target in first shot ) = n = 1/3

P(Bob hits the target in second shot ) = n^2 = ( 1/3 * 1/3 ) = 1/9

hence the probability of Bob winning( i.e. P( Bob wins Event E1 ) = n + n^2 = n ( 1 + n )

6 0

2 years ago

ASAP!!!!!!!!!!!!!!!!!!!

timama [110]

Answer:

Step-by-step explanation:

BC = 60

CA = 45

AB = sqrt(45^2 + 60^2)

AB = sqrt(2025 + 3600)

AB = sqrt(5625)

AB = 75

7 0

3 years ago

HELP plssssssssssssssssssssssss

hoa [83]

Answer: 8.5

Step-by-step explanation: 8.5 because 34 divided by 4 is 8.5. To find the unit rate, make 4 hours turn to 1 hour. To do that, divided 4 by 4. Do the same with the other number, which is 34. 34 divided 4 is equal to 8.5

7 0

2 years ago

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Graphing the sine function <br> Graph y= Sine (x)<br><br> Please include picture

kramer

Step-by-step explanation:

hop it help ..........

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8 0

2 years ago

Find the length of each side of the triangle determined by the three points P1,P2, and P3. State whether the triangle is an isos

Tanya [424]

Answer:

The triangle is both an Isosceles triangle and a right triangle.

Step-by-step explanation:

Given the vertices of a triangle.

$P_{1} = (- 1, 4)$

$P_{2} = (6, 2)$ and

$P_{3} = (4, - 5)$

We find the distance between all the points to determine the length of each side of the triangle.

Distance between any two points, say, $(x_1, y_1)$ and $(x_2, y_2)$ is:

$\sqrt{\bigg ( \textbf{x}_{\textbf{2}} \hspace{1mm} \textbf{- x}_{\textbf{1}} \bigg )^{\textbf{2}} \textbf{+} \bigg( \textbf{y}_{\textbf{2}} \hspace{1mm} \textbf{- y}_{\textbf{1}} \bigg)^ {\textbf{2}}$

Length between $P_1$ and $P_{2}$ , (Side 1) :

$(x_1, y_1) = (- 1, 4)$ and

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{\bigg(6 - (-1) \bigg)^{2} \hspace{1mm} + \hspace{1mm} \bigg( 2 - 4 \bigg )^2$

$= \sqrt{7^2 + 2^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}}$

Length of Side 1 = $\sqrt{\textbf{53}}$ units.

Distance between $P_1$ and $P_2$ , (Side 2):

$(x_1, y_1) = (-1, 4)$

$(x_2, y_2) = (4, - 5)$

Distance = $\sqrt{ \bigg( 4 + 1 \bigg)^2 \hspace{1mm} + \bigg( - 5 - 4 \bigg ) ^2$

$= \sqrt{ 25 + 81 }$

$= \sqrt{\textbf{106}}$

Length of Side 2 = $\sqrt{\textbf{106}}$ units.

Distance between $P_2$ and $P_3$ , Side 3 :

$(x_1, y_1) = (4, 5)$

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{ 2^2 \hspace{1mm} + \hspace{1mm} 7^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}$

Length of Side 3 = $\sqrt{\textbf{53}}$ units.

Note that the length of Side 1 = Length of Side 3.

That means the triangle is Isosceles.

Also, For a triangle to be right angle triangle, using Pythagoras theorem we have:

(Side 1)² + (Side 3)² = (Side 2)²

$\bigg( \sqrt{53} \bigg )^2 \hspace{1mm} + \hspace{1mm} \bigg( \sqrt{53} \bigg)^2 \hspace{1mm} = \hspace{1mm} \bigg ( \sqrt{106} \bigg ) ^2$

i.e, 53 + 53 = 106

Hence, the triangle is a right - angled triangle as well.

7 0

3 years ago