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natka813 [3]
4 years ago
6

Given the expression 12 over 12 to the third power.

Mathematics
2 answers:
4vir4ik [10]4 years ago
5 0
<u><em>Part 1:</em></u>
<u>Before we begin, you need to remember the following rule:</u>
\frac{x^a}{x^b} = x^{a-b}

<u>The given expression is:</u>
\frac{12}{12^3}

Since the base is the same in both numerator and denominator, we can apply the above rule. <u>This means that:</u>
\frac{12}{12^3} = 12¹⁻³ = 12⁻²

<u><em>Part 2:</em></u>
<u>Before we begin, you need to remember the following rule:</u>
x⁻ᵃ = \frac{1}{x^a}

Now, <u>from part 1</u>, we simplified the expression into 12⁻²
Since the power is negative, we can apply the above rule.
<u>This means that:</u>
12⁻² = \frac{1}{(12)^2} =  \frac{1}{12*12} = \frac{1}{144}

Hope this helps :)
Anon25 [30]4 years ago
5 0
Part A: You can subtract the exponents 1 and 3 to end up with 12^-2. Then, you can simplify it into a fraction.

Part B: 12 ^ -2 = 1 / (12^2) = 1 / 144 OR about 0.007
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Misha Larkins [42]

Answer:

15.8 in

Step-by-step explanation:

12cm  x .4 = 3 in

14 x .4 = 5.6

18 x .4 = 7.2

3 + 5.6 + 7.2 = 15.8 in

<em>Hope that helps!</em>

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8 0
3 years ago
Car dealership pays a wholesale price of $10,000 to purchase a vehicle if they mark up the price 20% what is the retail price of
xz_007 [3.2K]

Answer:

8000

Step-by-step explanation:

10000 x 20% = 2000

10000-2000= 8000

6 0
3 years ago
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 4.4 parts
Komok [63]

Solution:

To test the hypothesis is that the mean ozone level is different from 4.40 parts per million at 1% of significance level.

The null hypothesis and the alternative hypothesis is :

$H_0: \mu = 4.40$

$H_a: \mu \neq 4.40$

The z-test statistics is :

$z=\frac{\overline x - \mu}{\left( \sigma / \sqrt n \right)} $

$z=\frac{4.2 - 4.4}{\left(0.7 / \sqrt{23} \right)}  $

$z =\frac{-0.2}{0.145}$

z = -1.37

The z critical value for the two tailed test at 99% confidence level is from the standard normal table, he z critical value for a two tailed at 99% confidence is 2.57

So the z critical value for a two tailed test at 99% confidence is ± 2.57

Conclusion :

The z values corresponding to the sample statistics falls in the critical region, so the null hypothesis is to be rejected at 1% level of significance. There is a sufficient evidence to indicate that the mean ozone level is different from 4.4 parts per million. The result is statistically significant.

4 0
3 years ago
Find the 85th term of the arithmetic sequence - 25, 37, 49, ...
e-lub [12.9K]

Answer:

The 85 term of the arithmetic sequence would be 983

Step-by-step explanation:

Use the formula: an=a1+(n−1)d

an=a1+d(n-1)

a85= -25+(85-1)12

a85= -25+1008

a85=983

4 0
3 years ago
Read 2 more answers
How to do this question plz <br>question 2​
sashaice [31]

Answer:

a) x+3=19

Step-by-step explanation:

a)

x is the age of Ronald , Collin is three years older than Ronald , so if we add up x(Ronald's age) and 3(the difference between both of their ages), we would get Collin's age(19) . That is the explanation for this equation.

b)

x+3=19

x=19-3

x=16

thus , x is 16 , in other words , Ronald's age is 16.

3 0
4 years ago
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