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notsponge [240]
3 years ago
5

The slope of the line that contains the points (2, 14) and (3, 20) is 6. What is the y-intercept?

Mathematics
1 answer:
boyakko [2]3 years ago
8 0

Answer:

B. 2 [0, 2]

Step-by-step explanation:

Plug the coordinates into the Slope-Intercept Formula. It does not matter which ordered pair you choose:

20 = 6[3] + b

18

2 = b

y = 6x + 2

__________________________________________________________

14 = 6[2] + b

12

2 = b

y = 6x + 2

** You see? I told you that it did not matter which ordered pair you choose because you will always get the exact same result.

I am joyous to assist you anytime.

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The second on a watch is 14mm long. What area does it sweep through in 30 seconds
skad [1K]

Exact Area = 98pi  

Approximate Area = 307.8760800518 (use calculator stored version of pi)

Approximate Area = 307.72 (using pi = 3.14)

Units are in square millimeters

======================================================

Explanation:

In 60 seconds, the hand sweeps out a full circle of radius 14. The area of this circle is

A = pi*r^2 = pi*14^2 = 196pi

Half of this is what the hand sweeps out in 30 seconds, so A/2 = (196pi)/2 = 98pi is the exact area it sweeps out. Your calculator would then show 98pi = 307.8760800518 approximately

If instead you use pi = 3.14, then the approximate area is 98*3.14 = 307.72

3 0
3 years ago
3. Bob the Builder wants to earn an annual rate of 10% on his investments,
mamaluj [8]

Answer:

He should pay $2,790.7.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

E = P*I*t

In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time, in years.

After t years, the total amount of money is:

T = E + P

In this question:

Rate of 10%, so I = 0.1.

9 months, so t = \frac{9}{12} = 0.75

How much should he pay for a note that will be worth $3,000 in 9 months?

We have to find P for which T = 3000. So

T = E + P

3000 = E + P

E = 3000 - P

Then

E = P*I*t

3000 - P = P*0.1*0.75

1.075P = 3000

P = \frac{3000}{1.075}

P = 2790.7

He should pay $2,790.7.

8 0
3 years ago
The parabola below is a graph of the equation, -y+x=-4. Which of the points satisfy the inequality, -y+x ≤ -4 ? Check all that a
Bad White [126]
POINTED 6 CAYUSE ISV VERTICVAL

8 0
3 years ago
1) Write an equation that can be used to solve for the missing angles. (5pts)
algol13

Answer:

i dont know angles

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Please I need help with differential equation. Thank you
Inga [223]

1. I suppose the ODE is supposed to be

\mathrm dt\dfrac{y+y^{1/2}}{1-t}=\mathrm dy(t+1)

Solving for \dfrac{\mathrm dy}{\mathrm dt} gives

\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{y+y^{1/2}}{1-t^2}

which is undefined when t=\pm1. The interval of validity depends on what your initial value is. In this case, it's t=-\dfrac12, so the largest interval on which a solution can exist is -1\le t\le1.

2. Separating the variables gives

\dfrac{\mathrm dy}{y+y^{1/2}}=\dfrac{\mathrm dt}{1-t^2}

Integrate both sides. On the left, we have

\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\int\frac{\mathrm dz}{z+1}

where we substituted z=y^{1/2} - or z^2=y - and 2z\,\mathrm dz=\mathrm dy - or \mathrm dz=\dfrac{\mathrm dy}{2y^{1/2}}.

\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\ln|z+1|=2\ln(y^{1/2}+1)

On the right, we have

\dfrac1{1-t^2}=\dfrac12\left(\dfrac1{1-t}+\dfrac1{1+t}\right)

\displaystyle\int\frac{\mathrm dt}{1-t^2}=\dfrac12(\ln|1-t|+\ln|1+t|)+C=\ln(1-t^2)^{1/2}+C

So

2\ln(y^{1/2}+1)=\ln(1-t^2)^{1/2}+C

\ln(y^{1/2}+1)=\dfrac12\ln(1-t^2)^{1/2}+C

y^{1/2}+1=e^{\ln(1-t^2)^{1/4}+C}

y^{1/2}=C(1-t^2)^{1/4}-1

I'll leave the solution in this form for now to make solving for C easier. Given that y\left(-\dfrac12\right)=1, we get

1^{1/2}=C\left(1-\left(-\dfrac12\right)^2\right))^{1/4}-1

2=C\left(\dfrac54\right)^{1/4}

C=2\left(\dfrac45\right)^{1/4}

and so our solution is

\boxed{y(t)=\left(2\left(\dfrac45-\dfrac45t^2\right)^{1/4}-1\right)^2}

3 0
3 years ago
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