the value would be 2x10^7
It’s D I also trust the other guy
Answer : Probability that the pumping system will fail on any given day = 0.005
Explanation:
Probability that only older pump fail = P(A) = 0.10
Probability that only newer pump fail = P(B) = 0.05
Since they are independent events ,
then the conditions will be
P(A∩B) = P(A). P(B)
= 0.10 ×0.05
= 0.005
Hence, the probability will fail on any given day = 0.005
Proabably. 5 because if there is 2 sides on a coin then you should divide 10÷2 which is 5.
Answer:
.
Step-by-step explanation:
Probability that the car encounters a green light on the first day:
.
To meet the question's conditions, the car needs to encounter another green light on the second day. Given that the colors of the light on each day are "independent," the chance that there's a green light followed by another green light will be
.
- Condition is met on the first two days and green light on the third day:
. - Condition is met on the first three days and green light on the fourth day:
.
To meet the condition on the fifth day, there needs to be a yellow light. The probability that the condition is met on the first four days and on the fifth day will be
.
To meet the condition on the sixth day, all prior days should meet the conditions. Besides, there needs to be a red light on the sixth day. 
- Seventh day:

- Eighth day:
- Ninth day:
- Tenth day:
The question asks that the condition be met on all ten days. As a result, the probability of meeting the condition will be equal to the probability on the tenth day:
.