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Natali5045456 [20]
3 years ago
14

Solve - 5 3/4 - 3 1/2 = ???

Mathematics
2 answers:
IceJOKER [234]3 years ago
5 0

Answer:

-9 1/4 and as a decimal its (Decimal: -9.25)

Step-by-step explanation:

Hopefully i helped <3

ollegr [7]3 years ago
4 0

Answer:

-9 1/4

Step-by-step explanation:

- 5 3/4 - 3 1/2

= -23/4 - 7/2

= -23/4 - 14/4

= -37/4

= - 9 1/4

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Two pumps connected in parallel fail independently of one another on any given day. The probability that only the older pump wil
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Answer : Probability that the pumping system will fail on any given day = 0.005

Explanation:

Probability that only older pump fail = P(A) = 0.10

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then the conditions will be

P(A∩B) = P(A). P(B)

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Hence, the probability will fail on any given day = 0.005

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if you flip a coin 10 times, what is the best prediction​ possible for the number of times it will land on heads?
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4 0
2 years ago
Read 2 more answers
A traffic light at a certain intersection is green 50% of the time, yellow 10% of the time, and red 40% of the time. A car appro
kati45 [8]

Answer:

6.4\times 10^{-5} = 0.000064 = 0.0064\%.

Step-by-step explanation:

Probability that the car encounters a green light on the first day: 50 \% = 0.5.

To meet the question's conditions, the car needs to encounter another green light on the second day. Given that the colors of the light on each day are "independent," the chance that there's a green light followed by another green light will be

(0.5) \times 0.5 = 0.25.

  • Condition is met on the first two days and green light on the third day: (0.5 \times 0.5) \times 0.5 = 0.125.
  • Condition is met on the first three days and green light on the fourth day:   (0.5 \times 0.5 \times 0.5) \times 0.5.

To meet the condition on the fifth day, there needs to be a yellow light. The probability that the condition is met on the first four days and on the fifth day will be (0.5 \times 0.5 \times 0.5 \times 0.5) \times 0.1 = 0.5^{4} \times 0.1.

To meet the condition on the sixth day, all prior days should meet the conditions. Besides, there needs to be a red light on the sixth day. (0.5^{4} \times 0.1) \times 0.4

  • Seventh day: (0.5^{4} \times 0.1 \times 0.4 ) \times 0.4
  • Eighth day: (0.5^{4} \times 0.1 \times 0.4^2 ) \times 0.4
  • Ninth day: (0.5^{4} \times 0.1 \times 0.4^3 ) \times 0.4
  • Tenth day: (0.5^{4} \times 0.1 \times 0.4^4 ) \times 0.4 = 0.5^{4} \times 0.1 \times 0.4^{5}

The question asks that the condition be met on all ten days. As a result, the probability of meeting the condition will be equal to the probability on the tenth day: 0.5^{4} \times 0.1 \times 0.4^{5} = 6.4\times 10^{-5} = 0.000064 = 0.0064\%.

6 0
3 years ago
Read 2 more answers
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