12x-5y=20 y=x+4 3x+y=3 x=-y+3

1 answer:

4 0

Standard form (which I assume is what they want you to turn these into) is y=mx+b.

12x-5y=20 is y=2.4x-4.
Subtract 12x from both sides, -5y=-12x+20.
Multiply both sides by -1, 5y=12x-20.
Divide both sides by 5, y=2.4x-4.

y=x+4 is already in standard form- I'm not quite sure what to do.

3x+y=3 is y=-3x+3.
Subtract 3x from both sides, y=-3x+3.

x=-y+3 is y=-x+3
Ad y to both sides, y+x=3.
Subtract x from both sides, y=-x+3.

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What is an equation in slope-intercept form for the line that passes through the points (1 -3) and (3 1)

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Answer:
$y = 2x - 5$

Explanation:

Slope-intercept form formula:
$y = mx + b$
For this formula we need the slope to find the slope use the slope formula:
$\frac{y_{2} - y}{x_{2} - x}$
Plug in the two points (1,-3) and (3,1)
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Now use the slope-interpect formula and plug in the slope (m)
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The equation would be:
$y = 2x - 5$

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