All categories

3 years ago

Solve Y ___ + 5= 9 -6

Mathematics

1 answer:

kumpel [21]3 years ago

3 0

Answer: Y 24+5 = 9-6

Step-by-step explanation: First, subtract 5 from each side of the equation to isolate the y term while keeping the equation balanced:

−

Now, multiply each side of the equation by

−

to find

while keeping the equation balanced:

−

You might be interested in

In a bag, there are 2 red 4 blue 8 black and 2 yellow marbles. What is the probability of randomly selecting a blue marble

Assoli18 [71]

Answer:

Step-by-step explanation:

4/(2+4+8+2) = 4/16 = 1/4

5 0

3 years ago

Read 2 more answers

Solve the system of equation-5x+2y=9 y=7x

tangare [24]

X = 2y/5 - 9/5
y = 5x/2 + 9/2
(I don't know if this is correct)
Hope this helps!

7 0

3 years ago

What is ( -36x + 4 • 56x ) + ( 81x + 36 • 42x )

GREYUIT [131]

The answer to this expression is: 1781x

6 0

3 years ago

Read 2 more answers

PLEASEEE HELPPP!!!!

astra-53 [7]

The answer is B cause the 0 repeats multiple times

6 0

3 years ago

Find the scalar and vector projections of b onto a. a = −3, −6, 2 b = 1, 1, 2

scZoUnD [109]

Answer:

$comp_ab=\left(\dfrac{-5}{7}\right)$

$Proj_ab=\left$ .

Step-by-step explanation:

The given vectors are

$\vec{a}=,\vec{b}=$

Now,

$|\vec{a}|=\sqrt{(-3)^2+(-6)^2+(2)^2}$

$|\vec{a}|=\sqrt{9+36+4}$

$|\vec{a}|=\sqrt{49}$

$|\vec{a}|=7$

$\vec{a}\cdot \vec{b}=(-3)(1)+(-6)(1)+(2)(2)$

$\vec{a}\cdot \vec{b}=-3-6+4$

$\vec{a}\cdot \vec{b}=-5$

The scalar projection of b onto a is

$comp_ab=\left(\dfrac{\vec{a}\cdot \vec{b}}{|\vec{a}|}\right)$

$comp_ab=\left(\dfrac{-5}{7}\right)$

Vector projection of b onto a is

$Proj_ab=\left(\dfrac{\vec{a}\cdot \vec{b}}{|\vec{a}|}\right)\left(\dfrac{\vec{a}}{|\vec {a}|}\right)$

$Proj_ab=\left(\dfrac{-5}{7}\right)\left(\dfrac{}{7}\right)$

$Proj_ab=\left$

Therefore, scale and vector projections of b onto a are $comp_ab=\left(\dfrac{-5}{7}\right)$ and $Proj_ab=\left$ receptively.

3 0

3 years ago