<span>the limit as x approaches -3 of [g(x)-g(-3)]over(x+3) is the same as the derivative, or slope, of g(x) at the point x=-3, or g'(-3).
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = </span>
The closest one is 5 to the power of 1 over 3.
sq rt of 3 = 1.732
sq rt of 5 = 2.236
5^1/3 = 1.667
5^1/6 = 0.833
5^2/3 = 8.333
5^3/2 = 62.5
Answer:
a8 = 0.004
Step-by-step explanation:
Q is abt a geometric series given by the eqn: an = a1*r^(n-1)
given a1 = 40000, r = 0.1
an = 40000*(0.1)^(n-1)
a8 = 40000*(0.1)^(8-1)
= 40000*(0.1)^7
= 0.004
Answer: 17
21-4=17
4+17=21
21+17=38 and so on..
Assuming you want them multiplied
f(x)*g(x)=(3x+5)(x^2)=3x³+6x²