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3 years ago

Deanna estimated the product of 6.45 and 10.2 below.

Mathematics

2 answers:

Alex Ar [27]3 years ago

7 0

Answer:

b i am smart

Step-by-step explanation:

Bas_tet [7]3 years ago

5 0

Answer:

Step-by-step explanation:

I took the test

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Please help 8th grade math

wariber [46]

Answer:

$n \geq -\frac{-29}{28}$

Step-by-step explanation:

$-3(1 - 7n) \geq -32 - 8n\\-3 + 21n \geq -32 -8n\\$

+8n +8n

$-3 + 28n \geq -32\\+3 +3\\28n \geq -29\\/28 /28\\n \geq \frac{-29}{28}$

6 0

3 years ago

In the circle below, suppose m VUX = 152° and mZUVW = 77º. Find the following.

bezimeni [28]

Given:

In the circle, $m(\overarc{VUX})=152^\circ$ and $m(\angle MUV)=77^\circ$ .

To find:

The following measures:

(a) $m\angle VUX$

(b) $m\angle UXW$

Solution:

According to the central angle theorem, the central angle is always twice of the subtended angle intercepted on the same same arc.

$m(VUX)=2\times m\angle VWX$

$152^\circ=2\times m\angle VWX$

$\dfrac{152^\circ}{2}=m\angle VWX$

$76^\circ=m\angle VWX$

In a cyclic quadrilateral, the opposite angles are supplementary angles.

UVWX is a cyclic quadrilateral. So,

$m\angle VUX+m\angle VWX=180^\circ$ [Opposite angles of a cyclic quadrilateral]

$m\angle VUX+76^\circ=180^\circ$

$m\angle VUX=180^\circ-76^\circ$

$m\angle VUX=104^\circ$

Now,

$m\angle UXW+m\angle UVW=180^\circ$ [Opposite angles of a cyclic quadrilateral]

$m\angle UXW+77^\circ =180^\circ$

$m\angle UXW=180^\circ-77^\circ$

$m\angle UXW=103^\circ$

Therefore, $m\angle VUX=104^\circ$ and $m\angle UXW=103^\circ$ .

7 0

2 years ago

The graph of f(x) is shown. What is the value of f (x) when x= -2?

Elden [556K]

C. 3.5
You have to go to -2 on the “X axis” and find the corresponding “Y” value on the line.

7 0

3 years ago

Can anyone do any of these? :[

raketka [301]

Answer:

yes # 7

Step-by-step explanation:

729 times 59049

59778 is the answer

5 0

2 years ago

Read 2 more answers

A person invested $2,500 in an account growing at a rate allowing the money to

sveta [45]

Answer:

Step-by-step explanation:

A person invested $2,500 in an account growing at a rate allowing the money to double every 11 years. How long, to the nearest tenth of a year would it take for the

value of the account to reach $3,800?

The formula for exponential growth given as:

A(t) = Ao (1/2)^t/t½

A(t) = Amount after time t = $3,800

Ao = Initial amount invested = $2500

t = Time in years

t½ = Time it takes to double = 11 years

Hence,

3800 = 2500(1/2)^t/11

Divide both sides by 2500

3800/2500 = 2500(1/2)^t/11/2500

3 0

2 years ago