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vovikov84 [41]
3 years ago
15

Which is the equation of the circle?

Mathematics
1 answer:
Shkiper50 [21]3 years ago
5 0
Equation of a circle is given by:
(x-a)²+(y-b)²=r²
where (a,b) is the center of the circle and r is the radius. From the graph;
(a,b)=(-1,2) and r=7
thus plugging the values in the equation we get:
(x--1)²+(y-2)²=7²
simplifying the above we get:
(x+1)²+(y-2)²=49
hence we conclude that the answer is:
B](x+1)²+(y-2)²=49
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Anderson Systems is considering a project that has the following cash flow and WACC data. What is the project's NPV? Note that i
AURORKA [14]

Answer:

$265.65

Step-by-step explanation:

Given :

WACC: 9.00%

Year 0 1 2 3 Cash flows (-$1,000) $500 $500 $500

The NPV is calculated thus :

Initial cashflow + Σ additional cash flows / (1 + r)

Rate, r = 9% = 0.09

(1 + r) = (1 + 0.09) = 1.09

NPV = - 1000 + (500 / (1.09)¹ + (500 / 1.09)² + (500 / (1.09)³

NPV = - 1000 + 458.71559 + 420.83999 + 386.09174

NPV = 265.64732

NPV = 265.65 (2 DECIMAL PLACES)

5 0
3 years ago
PLEASE HELP!!! this test will bring my grade up!! (question in picture)
kipiarov [429]

Answer:

b

Step-by-step explanation:

I think it's SAS

It is because O is the common angle and the two sides are similar.

5 0
3 years ago
Which equation has 1 solution?<br><br> IwI = -2<br> IwI = -1<br> IwI = 0<br> IwI = - 1
vovangra [49]
Absolute value is alwas positive
so all of them excet the 3rd one are false

|w|=0 has 1 solution


if the last one was |w|=1 then ther would be 2 solutions, -1 and 1


answer is |w|=0
6 0
3 years ago
Help I dont know any of this!
Wewaii [24]

Answer:

i dont know it either im in 6th grade...

Step-by-step explanation:

5 0
3 years ago
The dimensions of a rectangular garden were 5m by 12m. Each dimensions was increased by the same amount. the garden has an area
Alex_Xolod [135]
Let's say, the amount that each side was increased was "a"
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we know the area is 120, so whatever "a" is, we know that

(5+a)(12+a) = 120

so   \bf (5+a)(12+a) = 120\implies 60+17a+a^2=120&#10;\\\\\\&#10;a^2+\underline{17} a\underline{-60}=0\qquad \qquad &#10;\begin{cases}&#10;20\cdot -3\implies \underline{-60}\\\\&#10;20-3\implies \underline{17}&#10;\end{cases}

use those factors, solve for "a"
4 0
3 years ago
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