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Finger [1]
3 years ago
7

On a piano, the formula to determine the frequency f of any pitch relative to the A above middle C (A440) is given by the expres

sion f(x)=440(2)x/12, where x represents the the number of half-steps above or below A440. Which of the following is equivalent to f(x)?
Mathematics
2 answers:
Nady [450]3 years ago
8 0

The answer is C. Just took the quiz and B was wrong. It needs to be the one with the smaller 12.

dolphi86 [110]3 years ago
3 0

Answer:

The answer is C on edge

Step-by-step explanation:

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
aev [14]

Answer: (B) -625

<u>Step-by-step explanation:</u>

Given the sequence {-500, -100, -20, -4, -0.8, ... }, we know that that the first term (a) is -500 and the ratio (r) is \dfrac{-100}{-500}=\dfrac{1}{5}

Input those values into the Sum formula:

S_n=\dfrac{a(1-r^n)}{1-r}\\\\S_8=\dfrac{-500\bigg(1-\dfrac{1}{5}^n\bigg)}{1-\dfrac{1}{5}}\\\\.\quad=\dfrac{-500\bigg(1-\dfrac{1}{390,625}\bigg)}{\dfrac{4}{5}}\\\\.\quad=\dfrac{-500\bigg(\dfrac{390,624}{390,625}\bigg)}{\dfrac{4}{5}}\\\\.\quad=\dfrac{5(-500)(390,624)}{4(390,625)}\\\\.\quad=-624.998\\\\.\quad=-625\quad \text{(rounded to 2 decimal places)}

4 0
3 years ago
A portable electronic typewriter cost £180 in 1988. Its price rose by 5% in 1989. What was the new price?
elena-s [515]

\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{5\% of 180}}{\left( \cfrac{5}{100} \right)180}\implies 9~\hfill \stackrel{\textit{new price}}{180+9\implies 189}

5 0
3 years ago
What is the equation of the circle that has a center at (-3, 1) and a radius of 5? A) (x + 3)2 + (y - 1)2 = 5 B) (x - 3)2 + (y +
Gnoma [55]

Answer:

C

Step-by-step explanation:

The vertex form of the equation of a circle is (x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center of the circle and r is the radius. This means that for the circle with center (-3,1) and radius 5 substitute into the vertex form these values. Substitute h = -3, k= 1, and r = 5. The equation becomes (x--3)^2 + (y-1)^2 = 5^2. This simplifies to (x+3)^2 + (y-1)^2 = 25. The solution is C.

7 0
3 years ago
Vector u has a magnitude of 7 units and a direction angle of 330°. Vector v has magnitude of 8 units and a direction angle of 30
Dafna11 [192]
Keeping in mind that x = rcos(θ) and y = rsin(θ).

we know the magnitude "r" of U and V, as well as their angle θ, so let's get them in standard position form.

\bf u=&#10;\begin{cases}&#10;x=7cos(330^o)\\&#10;\qquad 7\cdot \frac{\sqrt{3}}{2}\\&#10;\qquad \frac{7\sqrt{3}}{2}\\&#10;y=7sin(330^o)\\&#10;\qquad 7\cdot -\frac{1}{2}\\&#10;\qquad -\frac{7}{2}&#10;\end{cases}\qquad \qquad v=&#10;\begin{cases}&#10;x=8cos(30^o)\\&#10;\qquad 8\cdot \frac{\sqrt{3}}{2}\\&#10;\qquad \frac{8\sqrt{3}}{2}\\&#10;y=8sin(30^o)\\&#10;\qquad 8\cdot \frac{1}{2}\\&#10;\qquad 4&#10;\end{cases}

\bf u+v\implies \left( \frac{7\sqrt{3}}{2},-\frac{7}{2} \right)+\left( \frac{8\sqrt{3}}{2},4 \right)\implies \left( \frac{7\sqrt{3}}{2}+\frac{8\sqrt{3}}{2}~~,~~ -\frac{7}{2}+4\right)&#10;\\\\\\&#10;\left(\stackrel{a}{\frac{15\sqrt{3}}{2}}~~,~~  \stackrel{b}{\frac{1}{2}}\right)\\\\&#10;-------------------------------

\bf tan(\theta )=\cfrac{b}{a}\implies tan(\theta )=\cfrac{\frac{1}{2}}{\frac{15\sqrt{3}}{2}}\implies tan(\theta )=\cfrac{1}{15\sqrt{3}}&#10;\\\\\\&#10;\measuredangle \theta =tan^{-1}\left( \cfrac{1}{15\sqrt{3}} \right)\implies \measuredangle \theta \approx 2.20422750397203^o
8 0
3 years ago
Marcus states that the polynomial expression 3x3 – 4x2y + y2 + 2 is in standard form. Ariel states that it should be y2 – 4x2y +
lora16 [44]

Answer:

Here Ariel is wrong because 3x^3 is higher power than y^2

3x^3 goes first

then the mixed term -4x^2y

then the y^2

then the 2

So, Marcus is right

Standard form means that you write the terms by descending degree. here's main rules how to write polynomial expression in the standard form:

1. write the term with the highest exponent first (terms of third degree in our case 3x^3 );

2. write the terms with lower exponents in descending order (term -4x^2y followed by y^2 );

3. remember that a variable with no exponent has an understood exponent of 1 (here are no such terms);

4. a constant term (a number with no variable) always goes last (term 2).

4 0
3 years ago
Read 2 more answers
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