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Ulleksa [173]
3 years ago
13

The hypotenuse of a 45°-45°-90° triangle measures 8 inches. What is the length of each leg?

Mathematics
1 answer:
LenaWriter [7]3 years ago
4 0

Answer:

4.24, the hypotenuse is each leg multiplied by root 2, so you divide 6 by the root of 2

Step-by-step explanation:

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How do I do this. I don’t understand how to move place values
Drupady [299]

For this case we must indicate the value of the following expression, expressed in scientific notation:

(1.2 * 10^{-3}) * (1.1 * 10^{8}) =

We have that for multiplication properties of powers of the same base, the same base is placed and the exponents are added:

a ^ n * a ^ m = a ^ {n + m}

Then, rewriting the expression we have:

(1.2 * 1.1) * 10 ^{- 3 + 8} =\\1.32 * 10 ^ 5

Answer:

1.32 * 10 ^ 5

5 0
3 years ago
What is 15 percent of 50
gulaghasi [49]
15% x 50 = 7.5
You can search these up in a calculator or in google if you want. The answers should be online.
5 0
3 years ago
A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and
natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: E=k\frac{q}{r^{2} }; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: p=\frac{q}{A}; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: S=4\pi r^{2}; which gives us the surface of a sphere.

The inner surface: Si=4\pi (0.06m)^{2} = 0.04 m^{2}

The outer surface: S=4\pi (0.08m)^{2}=0.08m^{2}

Now we can calculate the charges,

Inner charge: Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC

Outer charge: Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC

Then, we are able to calculate both fields:

Inner field: Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}

Outer field:  Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0
3 years ago
0.5x+3.5=6 what is x
nasty-shy [4]

Answer:

5

Step-by-step explanation:

0.5x=6-3.5

0.5x=2.5

x=2.5÷0.5

x=5

6 0
3 years ago
Read 2 more answers
Simplify this algebraic expression completely. 10y – 3(y + 5) A. 7y – 15 B. 7y – 5 C. 7y + 2 D. 7y + 5
Kipish [7]
Hey! :)

10y-3(y+5)

Distribute the -3. 

-3*y= -3y  -3*5= -15

10y-3y-15

7y-15

"A" is the answer.

~'Manda
6 0
3 years ago
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