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denis23 [38]
3 years ago
5

(-2)(7)(-75)(3)(-2)=?

Mathematics
2 answers:
Serhud [2]3 years ago
5 0
Equals -6300 fjesshehw
timurjin [86]3 years ago
4 0

Answer:

-6300

Step-by-step explanation:

I just plugged it into my calculator, Google's works just fine :)

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M is directly proportional to r^2. When r=2 m=14. Work out the value of m when r=12
7nadin3 [17]

Answer:

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Step-by-step explanation:

7 0
3 years ago
Tootsie rolls cost $0.02 each and Peppermint Patties cost $0.05 each. If you have $1.00, how many of each
Julli [10]

Answer:

With $1 you can buy 50 Tootsie rolls, and 20 Peppermint Patties.

Step-by-step explanation:

100 divided by 2 = 50

100 divided by 5 = 20

4 0
3 years ago
Read 2 more answers
PLease help me asap!!!!!!!!!
SVETLANKA909090 [29]
A right triangle is = 90 degrees
7 0
4 years ago
What is the equation, in slope-intercept form, of the line that is perpendicular to the line
wlad13 [49]

Answer:

y=\frac{1}{2} x-1

Step-by-step explanation:

The initial line is given in "point-slope form" (y-y_0=m(x-x_0) therefore we can easily extract from it the slope, and obtain from it what should be the slope of a line perpendicular to it:

Given the expression: y-4=-2(x-6)

we understand that the slope is "-2", and the point through which the line passes is the point (6,4) on the plane. We are concerned about the slope, since a line perpendicular to the given line must have a slope that corresponds to the "opposite of the reciprocal" of the original slope.

The opposite of "-2" is "2", and the reciprocal of this is "1/2".

Therefore the slope of the perpendicular line must be "1/2".

Now we can build the equation of the line perpendicular line through the point (-2,-2) by using again the "point-slope form":

y-y_0=m(x-x_0)\\y-(-2)=\frac{1}{2} (x-(-2))\\y+2=\frac{1}{2} (x+2)

Solving for y in this last expression we express the line in slope_y-intercept form:

y+2=\frac{1}{2} (x+2)\\y+2=\frac{1}{2} x+1\\y=\frac{1}{2} x+1-2\\y=\frac{1}{2} x-1

6 0
4 years ago
Find the missing term (x^12)^5 x (x^-2)^9 x ? = (x^40)^5
Nata [24]
Let the missing term <span>be y
</span><span>(x^12)^5 x (x^-2)^9 x y = (x^40)^5
(x</span>∧60) x (x∧-18) x y = x∧200      (just multiply the powers together)
x∧60 ÷ x∧18 x y = x∧200     (just put the x∧-18 as divider (is that what it called) and the power will be positive)
x∧42 x y = x∧200   (cross out the x∧18 by minusing power 60 by 18)
y = x∧200 ÷ x∧42  (swapping the place)
y = x∧158

3 0
3 years ago
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