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jarptica [38.1K]
3 years ago
11

Assume the world catch of fish in 1950 was 12 million tons and in 1955 it was 96 million tons.

Mathematics
1 answer:
Rama09 [41]3 years ago
5 0

The rate of change is 16.8 million tons per year

<em><u>Solution:</u></em>

Given that, the world catch of fish in 1950 was 12 million tons and in 1955 it was 96 million tons

<em><u>The average rate of change is given by formula:</u></em>

\text{ Average rate of change } = \frac{\text{ change in value }}{\text{ number of years }}

Value in 1950 = 12 million tons

Value in 1955 = 96 million tons

Change in value = value in 1955 - value in 1950

Change in value = 96 million - 12 million = 84 million tons

Number of years = 1950 to 1955 = 5 years

<em><u>Substitute the given values in formula,</u></em>

<em><u></u></em>\text{ Average rate of change } = \frac{84 \text{ million tons}}{5} = 16.8 \text{ million tons}<em><u></u></em>

Thus rate of change is 16.8 million tons per year

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So there are 3 clubs:

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The number of combinations for each of these is given by the product between the number of students in the club, so we get:

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