All categories

2 years ago

Assume the world catch of fish in 1950 was 12 million tons and in 1955 it was 96 million tons.

Mathematics

1 answer:

Rama09 [41]2 years ago

5 0

The rate of change is 16.8 million tons per year

Solution:

Given that, the world catch of fish in 1950 was 12 million tons and in 1955 it was 96 million tons

The average rate of change is given by formula:

$\text{ Average rate of change } = \frac{\text{ change in value }}{\text{ number of years }}$

Value in 1950 = 12 million tons

Value in 1955 = 96 million tons

Change in value = value in 1955 - value in 1950

Change in value = 96 million - 12 million = 84 million tons

Number of years = 1950 to 1955 = 5 years

Substitute the given values in formula,

$\text{ Average rate of change } = \frac{84 \text{ million tons}}{5} = 16.8 \text{ million tons}$

Thus rate of change is 16.8 million tons per year

You might be interested in

Frances has piano lessons every fourth day.

Fiesta28 [93]

Answer: ask your teacher I’m not that smart

Step-by-step explanation:

7 0

2 years ago

Find gcd for 5767 and 4453

Dima020 [189]

The gcd of 5767 and 4453 is 73.
Hope this helps. :)

7 0

3 years ago

The average number of accidents is 3 per month, what is the probability of 1 accident?

tatuchka [14]

<h2>Hello!</h2>

The answer is: 33.33%

Since we have the average number of accidents that occurs in 1 month, and it's equal to 3, we can calculate the probability of 1 accident occurs by dividing it into the average number of accidents, using the following formula:

$Probability=\frac{FavorableOutcomes}{Outcomes}*100$

Where,

Favorable outcomes are the occurrence of the event, for this case, it's equal to 1.

Outcomes are the possible occurrence of the event, for this case, it's equal to 3.

So, by substituting we have:

$Probability=\frac{1}{3}*100$

$Probability=0.3333*100=33.33$

So, the probability will be equal to 33.33%

Have a nice day!

7 0

3 years ago

A storage tank will have a circular base of radius r and a height of r. The tank can be either cylindrical or hemispherical (ha

Neko [114]

Answer:

Volume: $\frac{2}{3}\pi r^3$

Ratio: $\frac{2}{9}r$

Step-by-step explanation:

First of all, we need to find the volume of the hemispherical tank.

The volume of a sphere is given by:

$V=\frac{4}{3}\pi r^3$

where

r is the radius of the sphere

V is the volume

Here, we have a hemispherical tank: a hemisphere is exactly a sphere cut in a half, so its volume is half that of the sphere:

$V'=\frac{V}{2}=\frac{\frac{4}{3}\pi r^3}{2}=\frac{2}{3}\pi r^3$

Now we want to find the ratio between the volume of the hemisphere and its surface area.

The surface area of a sphere is

$A=4 \pi r^2$

For a hemisphere, the area of the curved part of the surface is therefore half of this value, so $2\pi r^2$ . Moreover, we have to add the surface of the base, which is $\pi r^2$ . So the total surface area of the hemispherical tank is

$A'=2\pi r^2 + \pi r^2 = 3 \pi r^2$

Therefore, the ratio betwen the volume and the surface area of the hemisphere is

$\frac{V'}{A'}=\frac{\frac{2}{3}\pi r^3}{3\pi r^2}=\frac{2}{9}r$

6 0

2 years ago

Pls help...................

bearhunter [10]

First one b ≤ 9 good luck

5 0

2 years ago