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UNO [17]
3 years ago
10

Solve for x: −2(x + 3) = −2(x + 1) − 4. (1 point)

Mathematics
1 answer:
NeTakaya3 years ago
8 0

Answer:

Hey there!

Let's solve our equation below.

-2(x+3)= -2(x+1)-4

Let's distribute the parentheses.

-2x-6=-2x-2-4

We combine like terms.

-2x-6=-2x-6

We add 6 to both sides.

-2x=-2x

We divide both sides by -2

x=x

If, when solving an equation, you get one number or variable that equals itself, there are infinitely many solutions.

We can plug anything into this equation and it will always equal to same things, since x is just equal to whatever x value you want.

Therefore, there are infinitely many solutions.

I hope this helps!

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What percent of 29 is 3?
Fed [463]

I think the answer is 10.3%

5 0
3 years ago
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Please help with any of this Im stuck and having trouble with pre calc is it basic triogmetric identities using quotient and rec
german

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

#3

Let's start with sin here. \frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}} Therefore, because sin is y/r, r = \sqrt{5} and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = \frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}

#4

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = 4\sqrt{2}. Now, to find csc, we have to do r/y.

csc = \frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

#5

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = \sqrt{7/16} = \frac{\sqrt{7}}{4}

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = -\sqrt{7/9} = \frac{-\sqrt{7}}{3}

#6

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = (\frac{-\sqrt{6}}{2})^{2}

1 + cot^2 = 6/4

cot^2 = 2/4

cot = \frac{\sqrt{2}}{2}

tan = \sqrt{2}

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

(\frac{2}{\sqrt{2}})^2 + 1 = sec^2

4/2 + 1 = sec^2

2 + 1 = sec^2

sec^2 = 3

sec = -\sqrt{3}

cos = \frac{-\sqrt{3}}{3}

Hope this helps!! :)

3 0
3 years ago
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√20/125 answer in simpleset form<br>​
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Answer:

.4!

Step-by-step explanation:

first you divide 20 by 125 and get .16

then you take the square root of .16 and get .4

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3 years ago
Explain the two ways we can find the slope from an equation written in STANDARD FORM. Which way is more convenient and WHY?
Crank

Answer: Derivative or y = mx + b

Step-by-step explanation:

Take the m value from the standard form equation:

y = mx + b

Or, the second way, is to take the derivative of the function and plug in your x value for your slope.

The derivative of a linear function is very easy to take, so it boils to preference

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Answer:

x = 20

Step-by-step explanation:

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x +8 + 6x - 58 = 90

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