Question

The base edge of the regular triangular pyramid is b=10 cm and altitude of the base hb ≈ 8.66 cm. The slant height of the pyramid is k=8 cm. Find:
Lateral area of the pyramid

Answer 1

Answer:

The lateral area of the pyramid is $120\ cm^{2}$

Step-by-step explanation:

we know that

The lateral area of the pyramid is equal to the area of its three triangular lateral faces

so

$LA=3[\frac{1}{2}(b)(k)]$

where

$b=10\ cm$

$k=8\ cm$ ------> the slant height

substitute the values

$LA=3[\frac{1}{2}(10)(8)]=120\ cm^{2}$