Question

Find the equation of the straight line that passes through the points (1, 10) and (3, 2)

Answer 1

Answer:

y = -4x+14

Step-by-step explanation:

First find the slope

m = (y2-y1)/(x2-x1)

m = (2-10)/(3-1)

  =-8/2

  = -4

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

y = -4x+b

Substitute a point into the equation

10 = -4(1)+b

Add 4 to each side

14 = b

y = -4x+14

Answer 2

Answer:

y=-4x+14

Step-by-step explanation:

m=y1-y2/(x1-x2) and m= y-y1/x-x1

10-2/1-3=-4

m=-4     so          -4=y-10/x-1

                           -4x+4=y-10

                            -4x+14=y