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2 years ago

Find the equation of the straight line that passes through the points (1, 10) and (3, 2)

Mathematics

2 answers:

slava [35]2 years ago

8 0

Answer:

y = -4x+14

Step-by-step explanation:

First find the slope

m = (y2-y1)/(x2-x1)

m = (2-10)/(3-1)

=-8/2

= -4

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

y = -4x+b

Substitute a point into the equation

10 = -4(1)+b

Add 4 to each side

14 = b

y = -4x+14

mylen [45]2 years ago

5 0

Answer:

y=-4x+14

Step-by-step explanation:

m=y1-y2/(x1-x2) and m= y-y1/x-x1

10-2/1-3=-4

m=-4 so -4=y-10/x-1

-4x+4=y-10

-4x+14=y

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Oksana_A [137]

Answer:

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Step-by-step explanation:

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2 years ago

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Aneli [31]

Step-by-step explanation:

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3 years ago

A- CE=CD B- CE = CA C- BF=DF D- DF=EF please help!!

Oksana_A [137]

The perpendicular bisector theorem gives the statements that ensures

that $\overleftrightarrow{FG}$ and $\overleftrightarrow{AB}$ are perpendicular.

The two statements if true that guarantee $\overleftrightarrow{FG}$ is perpendicular to line $\overleftrightarrow{AB}$ are;

$\overline{CE} = \overline{CD}$

$\overline{DF} = \overline{EF}$

Reasons:

The given diagram is the construction of the line $\mathbf{\overleftrightarrow{FG}}$ perpendicular to line $\mathbf{\overleftrightarrow{AB}}$ .

Required:

The two statements that guarantee that $\overleftrightarrow{FG}$ is perpendicular to line $\overleftrightarrow{AB}$ .

Solution:

From the point C arcs E and D are drawn to cross line $\overleftrightarrow{AB}$ , therefore;

$\overline{CE} = \mathbf{\overline{CD}}$ arcs drawn from the same radius.

$\overleftrightarrow{FG}$ is perpendicular to line $\overleftrightarrow{AB}$ , given.

Therefore;

$\overline{DF} = \overline{EF}$ by perpendicular bisector theorem.

Learn more about the perpendicular bisector theorem here:

brainly.com/question/11357763

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2 years ago

Which expression is the simplest form of -(4x + y)n + 2(x - 3y)

Marina86 [1]

Answer:

$\boxed{\bold{-4nx-ny+2x-6y}}$

Explanation:

Rewrite:

= $\bold{-n\left(4x+y\right)+2\left(x-3y\right)}$

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= $\bold{-4nx-ny+2\left(x-3y\right)}$

Expand $\bold{2\left(x-3y\right): \ 2x-6y}$

= $\bold{-4nx-ny+2x-6y}$

Mordancy.

4 0

3 years ago

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pentagon [3]

Answer:

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Step-by-step explanation:

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