Answer:
your answers obviously 210
Answer:
9.18% probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 12, \sigma = 3](https://tex.z-dn.net/?f=%5Cmu%20%3D%2012%2C%20%5Csigma%20%3D%203)
What is the probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated?
This is 1 subtracted by the pvalue of Z when X = 16. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{16 - 12}{3}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B16%20-%2012%7D%7B3%7D)
![Z = 1.33](https://tex.z-dn.net/?f=Z%20%3D%201.33)
has a pvalue of 0.9082
1 - 0.9082 = 0.0918
9.18% probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated
Answer:
30 mins
Step-by-step explanation:
<em>speed = distance/ time </em>
speed of car A
= 20/ 12 km/ min
= 5/ 3 km/ min
also, speed of car A = speed of car B
speed of car B = 5/ 3 km/ min = 50km / time taken (in mins)
![\frac{5}{3} = \frac{50}{t}](https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B3%7D%20%20%3D%20%20%5Cfrac%7B50%7D%7Bt%7D%20)
![5t = 150](https://tex.z-dn.net/?f=5t%20%20%3D%20150)
![t = 30](https://tex.z-dn.net/?f=t%20%3D%2030)
=> t = 30 mins
Answer:
<h2>4x⁴yz - 16y³z = 4yz(x² - 2y)(x² + 2y)</h2>
Step-by-step explanation:
![4x^4yz-16y^3z\\\\4x^4yz=4yz\cdot x^4\\\\16y^3z=4yz\cdot4y^2\\\\4x^4yz-16y^3z=4yz\cdot x^4-4yz\cdot4y^2=4yz(x^4-4y^2)\\\\x^4-4y^2=x^{2\cdot2}-2^2y^2=(x^2)^2-(2y)^2=(x^2-2y)(x^2+2y)\\\\Used:\\\\(a^n)^m=a^{nm}\\\\(ab)^n=a^nb^n\\\\a^2-b^2=(a-b)(a+b)\\\\4x^4yz-16y^3z=4yz(x^2-2y)(x^2+2y)](https://tex.z-dn.net/?f=4x%5E4yz-16y%5E3z%5C%5C%5C%5C4x%5E4yz%3D4yz%5Ccdot%20x%5E4%5C%5C%5C%5C16y%5E3z%3D4yz%5Ccdot4y%5E2%5C%5C%5C%5C4x%5E4yz-16y%5E3z%3D4yz%5Ccdot%20x%5E4-4yz%5Ccdot4y%5E2%3D4yz%28x%5E4-4y%5E2%29%5C%5C%5C%5Cx%5E4-4y%5E2%3Dx%5E%7B2%5Ccdot2%7D-2%5E2y%5E2%3D%28x%5E2%29%5E2-%282y%29%5E2%3D%28x%5E2-2y%29%28x%5E2%2B2y%29%5C%5C%5C%5CUsed%3A%5C%5C%5C%5C%28a%5En%29%5Em%3Da%5E%7Bnm%7D%5C%5C%5C%5C%28ab%29%5En%3Da%5Enb%5En%5C%5C%5C%5Ca%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5C%5C%5C%5C4x%5E4yz-16y%5E3z%3D4yz%28x%5E2-2y%29%28x%5E2%2B2y%29)