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Tpy6a [65]
3 years ago
12

What is 15,409 in all forms

Mathematics
1 answer:
kotykmax [81]3 years ago
3 0
Siri use siri She has all the equations u will get it somehow
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What are the domain and range of the real-value function f(x) =-2+√x+7
stiks02 [169]

Because the function f(x) =-2+√x+7 has √x, x should be more or equal 0.

Domain is x≥0, or [0,+∞).

The smallest value of x=0, so the smallest value of f(x) is f(0) =-2+√0+7=5,

so range is f(x)≥5, or [5, +∞).

4 0
3 years ago
Read 2 more answers
Jason’s mom gave him 1,000 for his birthday. He put the money in the bank and decides to withdraw 25 per week.
Goshia [24]

Well 1000 for his birthday then subtract 25 each week, w, should be 1000-25w if i am not mistaken.

6 0
4 years ago
By what percentage did the price per ounce of gold increase
kkurt [141]

Answer:

The gold price increase from 1935, when President FDR raised gold value to $35 per ounce, compared to today's spot gold value of $1,335 represents an increase of approximately $3,700%.

5 0
3 years ago
Element X decays radioactively with a half life of 6 minutes. If there are 790 grams of Element X, how long, to the nearest tent
frosja888 [35]

Answer:

It takes 27 minutes for the element to decay to 35 grams

Step-by-step explanation:

Given:

Initial amount  =  790 grams

Final amount =  35 grams

Half life =  6 minutes

To find:

Time taken for the element to reduce into 35 grams  = ?

Solutions

Time taken = half life  \times \frac{ log(\frac{ initial amount}{final amount})}{log(2)}

On substituting the values given, Time taken  

= 6 \times \frac{log(\frac{790}{35})}{log(2)}

= 6 \times \frac{log(22.57)}{log(2)}

= 6 \times 4.496

= 26.97

= 27 minutes

7 0
3 years ago
The diameter of 0 gauge copper wire is 8.252 mm. Find the resistance (in ω) of a 2.40 km length of such wire used for power tran
VashaNatasha [74]

d = diameter of the copper wire = 8.252 mm

r = radius of the copper wire = d/2 = 8.252 mm /2 = 4.126 mm = 0.004126 m

A = area of cross-section of the copper wire = πr² = (3.14) (0.004126)² = 53.5 x 10⁻⁶

L = length of the copper wire = 2.40 km = 2400 m

ρ = resistivity of copper wire = 1.68 x 10⁻⁸

resistance of copper wire is given as

R = ρL/A

inserting the above values in the formula

R = ( 1.68 x 10⁻⁸)(2400)/(53.5 x 10⁻⁶)

R = 0.753 ohm

8 0
4 years ago
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