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4) 
Multiply by 2 on both sides
3m + 15 = 45
Subtract both sides by 15
3m = 30
Divide both sides by 3
so m = 3
5) 
Multiply both sides by 8
168 = q + 35
Subtract both sides by 35
q = 133
6) 
Subtract 14 from both sides
multiply by -11 on both sides
4x = 572
Divide both sides by 4
x= 143
7) 
Add 6 on both sides
Multiply both sides by 5
3c = 75
Divide both sides by 3
c = 25
8) 
Subtract both sides by 17
Multiply both sides by -2
t = -52
9) 
Multiply both sides by -7
42= 5p + 2
subtract 2 from both sides
40 = 5p
Divide both sides by 5
so p = 8
Answer: Option C) Raj forgot the negative when substituting -15+9x for y.
Solution:
(1) 9x-y=15
(2) 2x+8y=28
Isolating y in the first equation. Subtracting 9x both sides of the equation:
(1) 9x-y-9x=15-9x
Subtracting:
(1) -y=15-9x
Multiplying both sides of the equation by -1:
(1) (-1)(-y)=(-1)(15-9x)
(1) y=-15+9x
Then Raj found the value of y. It's not option D.
Substitutng y by -15+9x in the second equation:
(2) 2x+8(-15+9x)=28
Then option C) is the answer: Raj forgot the negative when substituting -15+9x for y.
Eliminating the parentheses applying the distributive property in the multiplication:
(2) 2x-120+72x=28
Adding similar terms:
(2) 74x-120=28
Solving for x. Adding 120 both sides of the equation:
(2) 74x-120+120=28+120
Adding:
(2) 74x=148
Dividing both sides of the equation by 74:
(2) 74x/74=148/74
Dividing:
(2) x=2
Solving for y: Replacing x by 2 in the first equation:
(1) y=-15+9x
(1) y=-15+9(2)
Multiplying:
(1) y=-15+18
Subtracting:
(1) y=3
No because They lose 12 sand that puts them at -12. Then they gain 5 which puts them at -7 and then they lose 8 which puts them at -15. Please mark as brainliest
