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3 years ago

I do not get this at all!!!

Mathematics

2 answers:

Anit [1.1K]3 years ago

8 0

Answer:

The answer is 4/30

olga nikolaevna [1]3 years ago

5 0

Answer:

Hi there!

The correct answer is 29%

Step-by-step explanation:

You first add all males numbers together and you get 14

and then since there is 4 freshmen, then you divide 4/14 and then multiply 100 to get a percentage and you round it up to 29%

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Consider functions f and g. Which expression is equal to f(x) ⋅ g(x) ?

zimovet [89]

Answer:

It has to be B or D

Step-by-step explanation:

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3 years ago

What is the value of x? two angles 8x-8, 7x+8

My name is Ann [436]

15x due to -8+8 being 0

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3 years ago

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Solve for H: A = L ⋅ W ⋅ H

Sergeu [11.5K]

Answer:

The answer would be

H = A over L times W

Step-by-step explanation:

This is because, when you multiply the L, W, and H you end up getting A. This means that A is the biggest number. We automatically can tell that H is what were looking for so putting those two things together we have this: H = A over ???

The ??? would have to be L times W because those are the only things left and they get multiplied together which in the end leaves us with

H = A over L times w

aka

H=A/LxW

6 0

3 years ago

Please help me with this question

MA_775_DIABLO [31]

Answer:

B. 36

Step-by-step explanation:

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3 years ago

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The position equation for a particle is s of t equals the square root of the quantity t cubed plus 1 where s is measured in feet

vladimir1956 [14]

$\bf s(t)=\sqrt{t^3+1}
\\\\\\
\cfrac{ds}{dt}=\cfrac{1}{2}(t^3+1)^{-\frac{1}{2}}\cdot 3t^2\implies \boxed{\cfrac{ds}{dt}=\cfrac{3t^2}{2\sqrt{t^3+1}}}\leftarrow v(t)
\\\\\\
\cfrac{d^2s}{dt^2}=\cfrac{6t(2\sqrt{t^3+1})-3t^2\left( \frac{3t^2}{\sqrt{t^3+1}} \right)}{(2\sqrt{t^3+1})^2}\implies 
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$\bf \cfrac{d^2s}{dt^2}=\cfrac{6t[2(t^3+1)]-1}{4(t^3+1)\sqrt{t^3+1}}\implies 
\boxed{\cfrac{d^2s}{dt^2}=\cfrac{12t^4+12t-1}{4t^3+4\sqrt{t^3+1}}}\leftarrow a(t)\\\\
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3 years ago

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