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Aloiza [94]
2 years ago
10

Bethany and Aidan each have candy bars that are the same size and shape. Bethany's candy bar is marked so that it can be broken

into equal parts. Aidan's candy bar is marked to that it can be broken into equal parts. Bethany ate pieces of her candy bar. Aidan also ate pieces of his candy. What is this problem about?
Mathematics
1 answer:
vivado [14]2 years ago
3 0

Answer:

Step-by-step explanation:

This problem is most likely about what percentage of the candy does each individual have left. Since the phrase is explaining that each ones candy bar is the same size and can be broken into equally divided pieces then it is most likely about figuring out which one of the individual's has more candy left over when compared to the other's candy. This is possible since both candies are the same size but more information would be needed.

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What is 52% of 25 if you answer your the first to answer you get 25 points
adoni [48]

Answer:

13

Step-by-step explanation:

convert 52% into a decimal which is 0.52 then mulitply by 25 to get your answer

5 0
3 years ago
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A circular pool with a diameter of 18 ft will have a uniform 4 ft concrete walkway poured around it. If the concrete cost $4.25
zysi [14]

A circular pool with a diameter of 18 ft will have a uniform 4 ft concrete walkway poured around it. If the concrete cost $4.25 a square foot, how much will it cost for the concrete?

This can be solve be solving the area of walkway

Area of walkway is equal to = (pi)( 9 ft +4) ^2– (pi)(9ft)^2

= 276.46 sq ft

Cost = 276.46 sq ft * ($4.25 a square foot) = $1174.70

4 0
3 years ago
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55 is 40% of what number
SCORPION-xisa [38]
You simply put 40 over a hundred and 55 over n (which is the number were trying to find)  so you do cross multiplication. 55 times a hundred and after you get the answer. You divide it by 40 and should get 137.5.
3 0
3 years ago
Find the coordinates of the image of point R(3, -5) rotated 180 degrees about the origin.
kolbaska11 [484]
180 degrees means that the new x=-x and the new y=-y so
x=3 and y=-5 is orignal
new is -3 and 5

so new oint is

A(-3,5)
6 0
3 years ago
x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
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