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Doss [256]
3 years ago
11

Describe at least three design decisions you could make to create a clear, effective presentation

Business
2 answers:
Veronika [31]3 years ago
6 0

Answer and explanation:

Different features make presentations effective. The most important is including only keywords in the presentation so the <em>explaining will be made by the presenter, including graphics and pictures to attract the audience, </em>and <em>keeping the same layout and registry for the information portrayed</em>.

olga_2 [115]3 years ago
4 0
Spacing, color, and contrast <span />
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(26000-6000)/5=4000
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Given the following linear demand forecast: Demand = 50 + 10 X (where X is the desired forecast period), what is the predicted f
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These are the four stages of the business cycle:
Brut [27]

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IT'S D

Explanation:

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3 years ago
During the year, Bears Inc. recorded credit sales of $620,000. Before adjustments at year-end, Bears has accounts receivable of
AleksandrR [38]

Answer:

Bad Debt Expense Dr. $28050        

Allowance for Uncollectible accounts Cr. $28050

Explanation:

given data

credit sales = $620,000

accounts receivable = $320,000

past due = $55,000

credit balance = $2,600

rate = 7 %

rate = 22 %

solution

so here Not yet past due is = $320,000 - $55,000 -

Not yet past due = $265,000

and

past due = $55,000

so  Required provision is

Required provision = $265,000 × 7 % + $55,000 × 22 %

Required provision = $30650

and

Opening balance is $2,600

so

Required expense for year = $30650 - $2,600

Required expense for year  = $28050

so here

correct entry is

Bad Debt Expense Dr. $28050        

Allowance for Uncollectible accounts Cr. $28050

8 0
3 years ago
What is the expected value when a $1 lottery ticket is bought in which the purchaser wins exactly $10 million if the ticket cont
Nadusha1986 [10]

We expect to lose $0.37 per lottery ticket

<u>Explanation:</u>

six winning numbers from = { 1, 2, 3, ....., 50}

So, the probability of winning:

P(win) = \frac{ no of favorable outcomes}{no of possible outcomes}

P(win) = \frac{1}{^5^0C_6} \\\\P (win) = \frac{6! X (50 - 6)!}{50!} \\\\P(win) = \frac{6! X 44!}{50!} \\\\P(win) = \frac{1}{15,890,700}

The probability of losing would be:

P(loss) = 1 - P(win)

P(loss) = 1 - \frac{1}{15,890,700} \\\\P(loss) = \frac{15,890,699}{15,890,700}

According to the question,

When we win, then we gain $10 million and lose the cost of the lottery ticket.

So,

$10,000,000 - 1 = $9,999,999

When we lose, then we lose the cost of the lottery ticket = $1

The expected value is the sum of the product of each possibility x with its probability P(x):

E(x) = ∑ xP(x)

= 9,999,999 X \frac{1}{15,890,700}  + ( -1 ) X \frac{15,890,699}{15,890,700} \\\\=- \frac{5,890,700}{15,890,700} \\\\= - \frac{58,907}{158,907} \\\\= - 0.37

Thus, we expect to lose $0.37 per lottery ticket

7 0
3 years ago
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