The answer is 11/36
2/12 chance of rolling fours
because there are 2 sides containing a four on both dice combined and 12 sides in total.
Doubles mean you have to roll the same number simultaneously so let’s say we want to calculate the probability for double ones: then it’s 1/6 on the first dice for a one, and 1/6 on the second dice to land on a one as well.
I personally like to imagine a box like this:
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If you have one dice then it’s just a random segment on one of the lines. If you want the specific result from two dice then you want two specific segments which is also the 1 specific tile out of 36 (6 width times 6 height). So you multiply.
1/6 * 1/6 = 1/36 chance to roll double of ones
And 1/36 chance to roll double twos, threes, fours, fives, and sixes. But we don’t count the double fours because any four will do. So:
1/36 * 5 = 5/36
So for the probability of either doubles or containing a four is the probability of doubles of either number plus the probability of either dice being a four:
5/36 + 2/12 =
5/36 + 6/36 =
11/36
35x100 hours = $3500+$65= $3565 for 100 hours of work and materials.
Answer:
25
Step-by-step explanation:
Hence 11% represents 25 students.
To answer equation there is only one solution which is, x=12
Answer:
312
Step-by-step explanation:
T.S.A : ( 2 × L × w ) + ( 2 × h × w ) + ( 2 × L × h ) = Area
9 - 3 = 6 - 3 = 3
( 2 × 12 × 3 ) + ( 2 × 8 × 3 ) + ( 2 × 12 × 8 ) = Area
72 + 48 + 192 = 312