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shepuryov [24]
3 years ago
13

A school is arranging a field trip to the zoo. The school spends 635.85 dollars on passes for 43 students and 2 teachers. The sc

hool also spends 367.22 dollars on lunch for just the students. How much money was spent on a pass and lunch for each student?
Mathematics
1 answer:
aalyn [17]3 years ago
7 0

Answer:

$22.67

Step-by-step explanation:

The school spends 635.85 dollars on passes for 43 students and 2 teachers, then the school spends

\$635.85 :(43+2)=\$14.13 per person.

The school also spends 367.22 dollars on lunch for just the students, so the school spends

\$367.22 :43=\$8.54 per person.

In total, a pass and lunch for each student was spent

\$14.13+\$8.54=\$22.67

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lakkis [162]
The answer to this question is 238
7 0
3 years ago
What is the value of 6n - 2 when n = 3?
svetoff [14.1K]

Answer:

Step-by-step explanation:

6n - 2

n = 3

substituting the value of n in the equation

6 × 3 - 2

= 18 - 2

= 16

hope this helps

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3 0
3 years ago
Sam is a waiter at a local restaurant where he earns wages of $7 per hour.
DochEvi [55]

Answer:

7h+5n=E

or

42+5n=E

Step-by-step explanation:

First write an equation : note key words like "per", "each" and "total".

7 per hour

5 each

6 hours

n= number of people

E= total earnings

total earnings

So:

7h+5n=E

$7 per hour plus $5 tips per person equals total earnings

7(6)+5n=E\\42+5n=E\\

3 0
3 years ago
in any given year a factory has a 10% probability of having a serious accident. about every how many years might the factory exp
Likurg_2 [28]

Years for one serious accident is 10 year

<u>Given:</u>

Probability of having a serious accident = 10% every year

P(serious accident) = 0.1

Number of years = n

<u>Computation:</u>

Years for one serious accident = 1 / Probability of having a serious accident

Years for one serious accident = 1 / P(serious accident)

Years for one serious accident = 1 / 0.1

Years for one serious accident = 10 year

Learn more:

brainly.com/question/23044118?referrer=searchResults

5 0
3 years ago
Let X denote the number of flaws along a 100-m reel of magnetic tape (an integer-valued variable). Suppose Zdenote the number of
Lemur [1.5K]

Answer:

a) P(20 \leq X \leq 30) = P(20-0.5 \leq X \leq 30+0.5)

P(19.5 \leq X \leq 30.5) = P(\frac{19.5-25}{5} \leq Z \leq \frac{30.5 -25}{5})=P(-1.1 \leq Z \leq 1.1)

And we can find this probability like this:

P(-1.1 \leq Z \leq 1.1)= P(Z\leq 1.1) -P(Z\leq -1.1) = 0.864-0.136= 0.728

b) P(X \leq 30)= P(X

And using the z score we got:

P(X

c) P(X

And if we use the continuity correction we got:

P(X

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Continuity correction means that we need to add and subtract 0.5 before standardizing the value specified.

Part a

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(25,5)  

Where \mu=25 and \sigma=5

Part a

For this case we want to find this probability:

P(20 \leq X \leq 30) = P(20-0.5 \leq X \leq 30+0.5)

And if we use the z score given by:

z =\frac{x-\mu}{\sigma}

We got this:

P(19.5 \leq X \leq 30.5) = P(\frac{19.5-25}{5} \leq Z \leq \frac{30.5 -25}{5})=P(-1.1 \leq Z \leq 1.1)

And we can find this probability like this:

P(-1.1 \leq Z \leq 1.1)= P(Z\leq 1.1) -P(Z\leq -1.1) = 0.864-0.136= 0.728

Part b

For this case we want this probability:

P(X \leq 30)

And if we use the continuity correction we got:

P(X \leq 30)= P(X

And using the z score we got:

P(X

Part c

For this case we want this probability:

P(X

And if we use the continuity correction we got:

P(X

3 0
3 years ago
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