To put an equation into (x+c)^2, we need to see if the trinomial is a perfect square.
General form of a trinomial: ax^2+bx+c
If c is a perfect square, for example (1)^2=1, 2^2=4, that's a good indicator that it's a perfect square trinomial.
Here, it is, because 1 is a perfect square.
To ensure that it's a perfect square trinomial, let's look at b, which in this case is 2.
It has to be double what c is.
2 is the double of 1, therefore this is a perfect square trinomial.
Knowing this, we can easily put it into the form (x+c)^2.
And the answer is: (x+1)^2.
To do it the long way:
x^2+2x+1
Find 2 numbers that add to 2 and multiply to 1.
They are both 1.
x^2+x+x+1
x(x+1)+1(x+1)
Gather like terms
(x+1)(x+1)
or (x+1)^2.
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Answer: A) is the right answer. 
Step-by-step explanation:
Given product : 
To multiply above expression, first we need to combine like terms and then we need to use the law of exponents.
![2.3\times3\times10^{-3}\times10^8\\=(2.3\times3)\times(10^{-3}\times10^8)\\=6.9\times10^{-3+8}......[\text{by law of exponents }a^n\cdot\ a^m=a^{m+n}]\\=6.9\times10^{5}](https://tex.z-dn.net/?f=2.3%5Ctimes3%5Ctimes10%5E%7B-3%7D%5Ctimes10%5E8%5C%5C%3D%282.3%5Ctimes3%29%5Ctimes%2810%5E%7B-3%7D%5Ctimes10%5E8%29%5C%5C%3D6.9%5Ctimes10%5E%7B-3%2B8%7D......%5B%5Ctext%7Bby%20law%20of%20exponents%20%7Da%5En%5Ccdot%5C%20a%5Em%3Da%5E%7Bm%2Bn%7D%5D%5C%5C%3D6.9%5Ctimes10%5E%7B5%7D)
Thus, the answer is .
