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tatiyna
3 years ago
10

How do you solve this a^2+b^2=c^2

Mathematics
1 answer:
DiKsa [7]3 years ago
7 0

Answer:

c = -\sqrt{a^2+b^2}

Step-by-step explanation:

-\sqrt{a^2+b^2=c}

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Which gives the correct values for points A, B, C, and D?
beks73 [17]

Answer:

The correct answer for this problem is the 2nd one because all you have to do is count how far each one is from -1 and -2

Step-by-step explanation:

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3 years ago
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You have exactly $120 to spend on a new outfit. If your state has 8% sales tax, what is the highest pre-price tax you can pay wi
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3 years ago
A plant produces 500 units/hour of an item with dimensions of 4” x 6” x 2”. The manager wants to store two weeks of supply in co
mart [117]

Answer:

  564 ft²

Step-by-step explanation:

To account for the extra space between units, we can add 2" to every unit dimension and every box dimension to figure the number of units per box.

Doing that, we find the storage box dimensions (for calculating contents) to be ...

  3 ft 2 in × 4 ft 2 in × 2 ft 2 in = 38 in × 50 in × 26 in

and the unit dimensions to be ...

  (4+2)" = 6" × (6+2)" = 8" × (2+2)" = 4"

A spreadsheet can help with the arithmetic to figure how many units will fit in the box in the different ways they can be arranged. (See attached)

When we say the "packing" is "462", we mean the 4" (first) dimension of the unit is aligned with the 3' (first) dimension of the storage box; the 6" (second) dimension of the unit is aligned with the 4' (second) dimension of the storage box; and the 2" (third) dimension of the unit is aligned with the 2' (third) dimension of the storage box. The "packing" numbers identify the unit dimensions, and their order identifies the corresponding dimension of the storage box.

We can see that three of the four allowed packings result in 216 units being stored in a storage box.

If storage boxes are stacked 4 deep in a 9' space, the 2' dimension must be the vertical dimension, and the floor area of each stack of 4 boxes is 3' × 4' = 12 ft². There are 216×4 = 864 units stored in each 12 ft² area.

If we assume that 2 weeks of production are 80 hours of production, then we need to store 80×500 = 40,000 units. At 864 units per 12 ft² of floor space, we need ceiling(40,000/864) = 47 spaces on the floor for storage boxes. That is ...

  47 × 12 ft² = 564 ft²

of warehouse floor space required for storage.

_____

The second attachment shows the top view and side view of units packed in a storage box.

4 0
3 years ago
For each bag belong, describe the likelihood of picking a black marble
liq [111]
In the first bag, picking a black marble would be impossible.

The second bag would be likely.

The third bag would be unlikely.

hope this helps!
3 0
3 years ago
I guess I'm lacking in differential equations. I couldn't solve this question. Can you help me?
Sonja [21]

Answer:

See Explanation.

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties
  • Reciprocals

<u>Algebra II</u>

  • Log/Ln Property: ln(\frac{a}{b} ) = ln(a) - ln(b)

<u>Calculus</u>

Derivatives

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Chain Rule: \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Derivative of Ln: \frac{d}{dx} [ln(u)] = \frac{u'}{u}

Step-by-step explanation:

<u>Step 1: Define</u>

ln(\frac{2x-1}{x-1} )=t

<u>Step 2: Differentiate</u>

  1. Rewrite:                                                                                                         t = ln(\frac{2x-1}{x-1})
  2. Rewrite [Ln Properties]:                                                                                 t = ln(2x-1) - ln(x - 1)
  3. Differentiate [Ln/Chain Rule/Basic Power Rule]:                                         \frac{dt}{dx} = \frac{1}{2x-1} \cdot 2 - \frac{1}{x-1} \cdot 1
  4. Simplify:                                                                                                          \frac{dt}{dx} = \frac{2}{2x-1} - \frac{1}{x-1}
  5. Rewrite:                                                                                                          \frac{dt}{dx} = \frac{2(x-1)}{(2x-1)(x-1)} - \frac{2x-1}{(2x-1)(x-1)}
  6. Combine:                                                                                                       \frac{dt}{dx} = \frac{-1}{(2x-1)(x-1)}
  7. Reciprocate:                                                                                                  \frac{dx}{dt} = -(2x-1)(x-1)
  8. Distribute:                                                                                                         \frac{dx}{dt} = (1-2x)(x-1)
8 0
3 years ago
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