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2 answers:
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The sum of the first n odd numbers is n squared! So, the short answer is that the sum of the first 70 odd numbers is 70 squared, i.e. 4900.
Allow me to prove the result: odd numbers come in the form 2n-1, because 2n is always even, and the number immediately before an even number is always odd.
So, if we sum the first N odd numbers, we have
The first sum is the sum of all integers from 1 to N, which is N(N+1)/2. We want twice this sum, so we have
The second sum is simply the sum of N ones:
So, the final result is
which ends the proof.
Answer with explanation:
The given mathematical expression to solve :
The prime factorization of each term can be written as follows :-
We can see that the greatest common factor of both the terms =
So we rewrite the given expression as :-
By using distributive property :-
, we have