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2 years ago

01:41:17

Mathematics

1 answer:

Vlad [161]2 years ago

8 0

Answer: 69

Step-by-step explanation:

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Step-by-step explanation:

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Read 2 more answers

Factor the quadratic expression in the equation y=2x^2+28x+96 and use the factors to find the zeros of the equation. Then, use t

gavmur [86]

Answer:

$x=-7$

Step-by-step explanation:

We have been given an equation $y=2x^2+28x+96$ . We are asked to find the zeros of equation by factoring and then find the line of symmetry of the parabola.

Let us factor our given equation as:

$2x^2+28x+96=0$

Dividing both sides by 2:

$x^2+14x+48=0$

Splitting the middle term:

$x^2+6x+8x+48=0$

$(x^2+6x)+(8x+48)=0$

$x(x+6)+8(x+6)=0$

$(x+8)(x+6)=0$

Using zero product property:

$(x+8)=0\text{ (or) }(x+6)=0$

$x+8=0\text{ (or) }x+6=0$

$x=-8\text{ (or) }x=-6$

Therefore, the zeros of the given equation are $x=-8\text{ (or) }x=-6$ .

We know that the line of symmetry of a parabola is equal to the x-coordinate of vertex of parabola.

We also know that x-coordinate of vertex of parabola is equal to the average of zeros. So x-coordinate of vertex of parabola would be:

$\frac{-8+(-6)}{2}=\frac{-14}{2}=-7$

Therefore, the equation $x=-7$ represents the line of symmetry of the given parabola.

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2 years ago