Tensile strength tests were performed on two different grades of aluminum spars used in manufacturing the wing of a commercial t
ransport aircraft. From past experience with the spar manufacturing process and the testing procedure, the standard deviations of tensile strengths are assumed to be known. The data obtained are as follows: n_1 = 10 and x_1 = 87.6 sigma_1 = 1 and n_2 = 12 x^2 = 74.5 sigma_2 = 1.5. If mu_1 and mu_2 denote the true mean tensile strengths for the two grades of spars. Construct a 90 percentage confidence interval on the .difference in mean strength.
Given that Tensile strength tests were performed on two different grades of aluminum spars used in manufacturing the wing of a commercial transport aircraft. From past experience with the spar manufacturing process and the testing procedure, the standard deviations of tensile strengths are assumed to be known.
Group Group One Group Two
Mean 87.600 74.500
SD 1.000 1.500
SEM 0.316 0.433
N 10 12
The mean of Group One minus Group Two equals 13.100
The only reason an inequality would change would be because a number is divided or multiplied by a negative number. So if it stayed the same, then it would be because there was no division or multiplication by a negative number. Hope I helped :)
