Angle 3 and angle 6 are an example of which type of angle pair ?

Match the graph with its equation.

hram777 [196]

The equation to this is A 5X+4Y=-20

5 0

3 years ago

How many 5 1/4 ounce glasses can be completely filled from a 33 1/2 ounce container of juice?

geniusboy [140]

You need to divide.
We are dividing the mixed numeral 33 1/21 by the mixed numeral 5 1/4.

(33 1/2 ) / (5 1/4) =

The first step is to change the two mixed numerals into improper fractions.
33 1/2 = 67/2, and 5 1/4 = 21/4

= (67/2) / (21/4)

Now we are dividing the fraction 67/2 by the fraction 21/4.
To divide a fraction by a fraction, rewrite the first fraction, change division intro multiplication, and flip the second fraction. To divide 67/2 by 21/4, we multiply 67/2 by 4/21.

= 67/2 * 4/21

To multiply fractions, multiply together the numerators, and multiply together the denominators. 67 * 4 = 268; 2 * 21 = 42

= 268/42

Using a calculator, 268/42 = 6.38095...

You can fill 6 full glasses.

5 0

3 years ago

How do i complete the rest of the table

Rufina [12.5K]

To find Vanilla for ages 8-12, you add up the known amount from each flavor for that age group and subtract it from the total to get... 50 - (25 + 12) = 13
To find Chocolate for ages 13-17, you add up the amount of people know to pick up late and subtract it from the total amount of people who picked chocolate to get... 100 - (35 + 25) = 40
Now that we have that number, we can use it to find the amount of people ages 13-17 who chose Vanilla. To find this you subtract the total amount of people who chose chocolate and strawberry from the total amount of people to get... 80 - (40 + 12) = 28

This should help :)

4 0

3 years ago

Read 2 more answers

You roll two dice. What is the probability you get a 2 and a number greater than 2?

abruzzese [7]

Hello!

You have to find the probability of getting a 2

This is a 1/6 chance

Then you have to find the chance of getting a number greater than 2

This is a 4/6 chance

To find the chance of these happening at the same time you multiply these together

1/6 * 4/6 = 1/9

There is a 1/9 chance

Hope this helps!

6 0

3 years ago

Read 2 more answers

Refer to the following scenario:You want to see if there is a difference between the exercise habits of Science majors and Math

bekas [8.4K]

Answer:

1. H0: P1 = P2

2. Ha: P1 ≠ P2

3. pooled proportion p = 0.542

4. P-value = 0.0171

5. The null hypothesis failed to be rejected.

At a signficance level of 0.01, there is not enough evidence to support the claim that there is significant difference between the exercise habits of Science majors and Math majors .

6. The 99% confidence interval for the difference between proportions is (-0.012, 0.335).

Step-by-step explanation:

We should perform a hypothesis test on the difference of proportions.

As we want to test if there is significant difference, the hypothesis are:

Null hypothesis: there is no significant difference between the proportions (p1-p2 = 0).

Alternative hypothesis: there is significant difference between the proportions (p1-p2 ≠ 0).

The sample 1 (science), of size n1=135 has a proportion of p1=0.607.

$p_1=X_1/n_1=82/135=0.607$

The sample 2 (math), of size n2=92 has a proportion of p2=0.446.

$p_2=X_2/n_2=41/92=0.446$

The difference between proportions is (p1-p2)=0.162.

$p_d=p_1-p_2=0.607-0.446=0.162$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{82+41}{135+92}=\dfrac{123}{227}=0.542$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.542*0.458}{135}+\dfrac{0.542*0.458}{92}}\\\\\\s_{p1-p2}=\sqrt{0.001839+0.002698}=\sqrt{0.004537}=0.067$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.162-0}{0.067}=\dfrac{0.162}{0.067}=2.4014$

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

$\text{P-value}=2\cdot P(z>2.4014)=0.0171$

As the P-value (0.0171) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

At a signficance level of 0.01, there is not enough evidence to support the claim that there is significant difference between the exercise habits of Science majors and Math majors .

We want to calculate the bounds of a 99% confidence interval of the difference between proportions.

For a 99% CI, the critical value for z is z=2.576.

The margin of error is:

$MOE=z \cdot s_{p1-p2}=2.576\cdot 0.067=0.1735$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.162-0.1735=-0.012\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.162+0.1735=0.335$

The 99% confidence interval for the difference between proportions is (-0.012, 0.335).

6 0

3 years ago