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3 years ago

Which algebraic expression is equivalent to the expression below?

Mathematics

1 answer:

kenny6666 [7]3 years ago

5 0

Answer:

C. 4( 2x+1 )

Step-by-step explanation:

12x+4-4x = 8x+4

A. 8(x + 1) = 8x+8

B. 4(2x - 1) = 8x-4

C.4(2x + 1) = 8x+4

D. 4(x + 1) = 4x+4

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Which of the following equations has no solutions?

hammer [34]

May. Be D

Am I right

3 0

2 years ago

Can you help me find the measure of each angle? Diagram attached

never [62]

Answer:

5x = 100°

4x = 80°

Step-by-step explanation:

We are given a diagram with a straight line AC being intersected by another line BD and we are to find the two mentioned angles.

We know that the two angles (5x° and 4x°) are supplementary so their sum would be equal to 180°.

So we can write it as:

$5x+4x=180$

$9x=180$

$x=\frac{180}{90}$

$x=20$

Finding the measure of both the angles:

$5x = 5(20) =$ 100°

$4x = 4(20) =$ 80°

4 0

2 years ago

Read 2 more answers

Han earned $850 over the summer working odd jobs. He wants to put his money into a savings account for when he is ready to buy a

Naily [24]

Answer:

85 in intreset and 935 totoal

Step-by-step explanation:

Answer:

A = $935.00

I = A - P = $85.00

Equation:

A = P(1 + rt)

Calculation:

First, converting R percent to r a decimal

r = R/100 = 5%/100 = 0.05 per year.

Solving our equation:

A = 850(1 + (0.05 × 2)) = 935

A = $935.00

The total amount accrued, principal plus interest, from simple interest on a principal of $850.00 at a rate of 5% per year for 2 years is $935.00.

4 0

3 years ago

Read 2 more answers

E=6c^2-2c-1 F=-4c^2+7c+5 E+F=

kifflom [539]

Answer:

E + F = 2c^2 + 5c + 4

Step-by-step explanation:

E=6c^2-2c-1

F=-4c^2+7c+5

E+F= 6c^2 -2c -1 + -4c^2 + 7c + 5

E + F = 6c^2 - 4c^2 - 2c + 7c - 1 + 5

E + F = 2c^2 + 5c + 4

4 0

2 years ago

What is the interquartile range of this set of data? 15,19,20,25,31,38,41

cupoosta [38]

Answer: 19.

Step-by-step explanation:

1: Place your numbers in numerical order from smallest to largest; 15,19,20,25,31,38,41.

2. Find your median in the set of numbers; 15,19,20,25,31,38,41.

3. Find Q1 and Q3 in your set of numbers by placing parentheses around the median you have just found. (15,19,20),25,(31,38,41.)

4. In this instance, you need to find the medians of the two number sets in parentheses; (15,19,20), 19 being Q1, and (31,38,41), 38 being Q3.

5. Using the interquartile range formula; Q3-Q1= IQR, plug in your numbers.

38-19=19, making the answer 19.

7 0

2 years ago