![\bf a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad \cfrac{1}{a^{ n}}\implies a^{-{ n}} \\ \quad \\ % negative exponential denominator a^{{ n}} \implies \cfrac{1}{a^{- n}} \qquad \qquad \cfrac{1}{a^{- n}}\implies \cfrac{1}{\frac{1}{a^{ n}}}\implies a^{{ n}} \\\\ -----------------------------\\\\ \cfrac{4xy}{mn^5}\implies \cfrac{4xy}{1}\cdot \cfrac{1}{m^1}\cdot \cfrac{1}{n^5}\implies 4xym^{-1}n^{-5}](https://tex.z-dn.net/?f=%5Cbf%20%20a%5E%7B-%7B%20n%7D%7D%20%5Cimplies%20%5Ccfrac%7B1%7D%7Ba%5E%7B%20n%7D%7D%5Cqquad%20%5Cqquad%0A%5Ccfrac%7B1%7D%7Ba%5E%7B%20n%7D%7D%5Cimplies%20a%5E%7B-%7B%20n%7D%7D%0A%5C%5C%20%5Cquad%20%5C%5C%0A%25%20%20negative%20exponential%20denominator%0Aa%5E%7B%7B%20n%7D%7D%20%5Cimplies%20%5Ccfrac%7B1%7D%7Ba%5E%7B-%20n%7D%7D%0A%5Cqquad%20%5Cqquad%20%0A%5Ccfrac%7B1%7D%7Ba%5E%7B-%20n%7D%7D%5Cimplies%20%5Ccfrac%7B1%7D%7B%5Cfrac%7B1%7D%7Ba%5E%7B%20n%7D%7D%7D%5Cimplies%20a%5E%7B%7B%20n%7D%7D%20%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0A%5Ccfrac%7B4xy%7D%7Bmn%5E5%7D%5Cimplies%20%5Ccfrac%7B4xy%7D%7B1%7D%5Ccdot%20%5Ccfrac%7B1%7D%7Bm%5E1%7D%5Ccdot%20%5Ccfrac%7B1%7D%7Bn%5E5%7D%5Cimplies%204xym%5E%7B-1%7Dn%5E%7B-5%7D)
notice, all you do is, move the factor from the bottom to the top, or from the top to the bottom, and the sign changes, from negative to positive or the other way around, is all there's on that
Answer:
7 green cars.
Step-by-step explanation:
Look at the totals of all of the colors at the bottom. The least of them is green (at 7 cars). That's the answer.
The missing reason to complete Hector's proof is
<span>Corresponding Parts of Congruent Triangles Are Congruent
It's been established in the previous statement that triangle LNO and triangle PNM are congruent by the AAS Postulate.
The proof
</span>Corresponding Parts of Congruent Triangles Are Congruent
is comprehensive.
Answer:
So first you have to do 12-2 since it's in parenthesis. It is 10. 5+4 is 9, and 9 times 10 is 90. 3 squared is 9, then you divide 90 by 9. The answer is 10.
Answer:
- apple: £0.20
- banana: £0.60
Step-by-step explanation:
Let "a" and "b" represent the costs of one apple and one banana, respectively. Then the purchases can be written ...
4a +b = 1.40
7a +b = 2.00
Subtracting the first equation from the second gives ...
(7a +b) -(4a +b) = (2.00) -(1.40)
3a = 0.60 . . . . simplify
a = 0.20 . . . . . .divide by 3
Using this in the first equation, we have ...
4(0.20) +b = 1.40
b = 0.60 . . . . . subtract 0.80
The cost of an apple is £0.20; the cost of a banana is £0.60.