Answer:
H0: μ = 5 versus Ha: μ < 5.
Step-by-step explanation:
Given:
μ = true average radioactivity level(picocuries per liter)
5 pCi/L = dividing line between safe and unsafe water
The recommended test here is to test the null hypothesis, H0: μ = 5 against the alternative hypothesis Ha: μ < 5.
A type I error, is an error where the null hypothesis, H0 is rejected when it is true.
We know type I error can be controlled, so safer option which is to test H0: μ = 5 vs Ha: μ < 5 is recommended.
Here, a type I error involves declaring the water is safe when it is not safe. A test which ensures that this error is highly unlikely is desirable because this is a very serious error. We prefer that the most serious error be a type I error because it can be explicitly controlled.
≠ means not equal to
L x w = 36
2L + 2w = 30
1. Find the multiples of 36
1 and 36
2 and 18
3 and 12
4 and 9
6 and 6
2. Figure out which set of numbers multiplied by 2 equals 30.
For 1 and 36:
2(1) + 2(36) = 2 + 72 = 74 ≠ 30
For 2 and 18:
2(2) + 2(18) = 4 + 32 = 36 <span>≠ 30
For 3 and 12:
2(3) + 2(12) = 6 + 24 = 30
So your answer is 3 and 12</span>
Answer:
The answer is 23.
Step-by-step explanation:
Our equation here is (2x + y) + 5.
If x=4, and y=10, let's plug that in into our variables, and simplify!
[2(4) + (10)] + 5
= [8+10] + 5
=[18] +5
=23
