Question

If g (x)= x+1/x-2 and h(x) =4-c, what is the value of (g•h)(-3)?

Answer 1

Answer:

Step-by-step explanation:

g(h(-3)) = g(7)

As h(x)= 4-x so h(-3) = 4+3=7

(g•h)(-3)= g(7) = 7+1/7-2= 8/5

Answer 2

Answer:

$g(h(-3)) = \frac{8}{5}$

Step-by-step explanation:

Given:

$g(x)=\frac{x+1}{x-2}$

$h(x)=4-x$

Find $g(h(-3))$

What this problem is asking is find the value of $h(-3)$ and then put that answer into $g(x).$

Let's find $h(-3)$.

$h(x)=4-x\\h(-3)=4-(-3)\\h(-3)=7$

Now that we found that $h(-3)$ is equal to 7, we put the value of 7 into $g(x).$

$g(x)=\frac{x+1}{x-2}\\g(7)=\frac{7+1}{7-2} \\g(7)=\frac{8}{5}$

Our final answer is

$g(h(-3)) = \frac{8}{5}$