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Y_Kistochka [10]
3 years ago
10

If g (x)= x+1/x-2 and h(x) =4-c, what is the value of (g•h)(-3)?

Mathematics
2 answers:
Kay [80]3 years ago
8 0

Answer:

Step-by-step explanation:

g(h(-3)) = g(7)

As h(x)= 4-x so h(-3) = 4+3=7

(g•h)(-3)= g(7) = 7+1/7-2= 8/5

nignag [31]3 years ago
3 0

Answer:

g(h(-3)) = \frac{8}{5}

Step-by-step explanation:

Given:

g(x)=\frac{x+1}{x-2} \\

h(x)=4-x

Find g(h(-3))

What this problem is asking is find the value of h(-3) and then put that answer into g(x).

Let's find h(-3).

h(x)=4-x\\h(-3)=4-(-3)\\h(-3)=7

Now that we found that h(-3) is equal to 7, we put the value of 7 into g(x).

g(x)=\frac{x+1}{x-2}\\g(7)=\frac{7+1}{7-2} \\g(7)=\frac{8}{5}

Our final answer is

g(h(-3)) = \frac{8}{5}

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